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nfa1rhp
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average = s/n

in ounce, the average = \((s*16)/n\)
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Bunuel, how can we plug in numbers for this one? This one looks simple, but for some reason, I'm having a hard time seeing if I'm doing it correctly...

Is this right?
n = 3 (for 3 fish)
s = 3 (each fish to weight 1 pound each. There are 3 fish so this equals to 3 pounds (total)).

Plugging into answer choice B) 16(3)/3 = 16 (since 16 is the average weight of the fish in ounces).
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