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Now I started thinking about it:

Is this a general rule that: X percent of Y is always equals to Y percent of X (for two completely random unrelated numbers)?

Because:
(X/100)*Y=(Y/100)*X

Did I get it right?
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Yes, that is correct
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Fijisurf
Integers X, Y and Z are greater than zero.
Is X percent of Y more than Y percent of Z?

(1) Z-Y=Y-Z
(2) X=Z


How do I approach this?
Thanks.

Come to think of it,
Statement (1) just says Z - Y = Y - Z which gives 2Z = 2Y or Z = Y. So your question becomes: Is X% of Y > Y% of Y? No information about X so not sufficient.
Statement (2) says X = Z. so your question is: Is X% of Y > Y% of X. As you have already discussed it with shrouded1 above, this is sufficient.
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VeritasPrepKarishma
Fijisurf
Integers X, Y and Z are greater than zero.
Is X percent of Y more than Y percent of Z?

(1) Z-Y=Y-Z
(2) X=Z


How do I approach this?
Thanks.

Come to think of it,
Statement (1) just says Z - Y = Y - Z which gives 2Z = 2Y or Z = Y. So your question becomes: Is X% of Y > Y% of Y? No information about X so not sufficient.
Statement (2) says X = Z. so your question is: Is X% of Y > Y% of X. As you have already discussed it with shrouded1 above, this is sufficient.

It makes perfect sense now.
I think this was the hardest percent Q I have ever seen so far.
Do you guys know any other tough questions testing percent knowledge here on the forum?
Thanks
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Fijisurf
VeritasPrepKarishma
Fijisurf
Integers X, Y and Z are greater than zero.
Is X percent of Y more than Y percent of Z?

(1) Z-Y=Y-Z
(2) X=Z


How do I approach this?
Thanks.

Come to think of it,
Statement (1) just says Z - Y = Y - Z which gives 2Z = 2Y or Z = Y. So your question becomes: Is X% of Y > Y% of Y? No information about X so not sufficient.
Statement (2) says X = Z. so your question is: Is X% of Y > Y% of X. As you have already discussed it with shrouded1 above, this is sufficient.

It makes perfect sense now.
I think this was the hardest percent Q I have ever seen so far.
Do you guys know any other tough questions testing percent knowledge here on the forum?
Thanks

Tags list by forum: viewforumtags.php

DS questions on percents: search.php?search_id=tag&tag_id=192
PS questions on percents: search.php?search_id=tag&tag_id=191

Theory: math-number-theory-percents-91708.html

Hope it helps.
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(X% of Y ) > (Y% of Z)
XY>YZ
X>Z

So ,actually we need relation between X and Z . Only option B has both X and Z . So option B is the answer
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