Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Jun 1111:00 AM EDT
-01:00 PM EDT
TTP GMAT OnDemand gives serious students 400+ hours of expert video instruction, the full TTP course, AI support, weekly office hours, and a 715+ score guarantee—all built for elite GMAT score improvement.
Jun 2207:30 PM EDT
-09:30 PM EDT
Master the GMAT with expert live instruction, a personalized study plan, and real-time support. Includes 40 hours of online classes plus 6 months of access to the TTP GMAT OnDemand video course. Class date: Mon/Wed June 22, 2026 →August 26, 2026
25 Jan 2011, 06:51
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:49) correct
25%
(01:58)
wrong
based on 194
sessions
History
Date
Time
Result
Not Attempted Yet
Is 4m - 5n > m^2
(1) n < 0
(2) m is an integer between 0 and 4 inclusive
(1) n < 0
(2) m is an integer between 0 and 4 inclusive
25 Jan 2011, 07:01
Kudos
Bookmarks
rxs0005
Is \(4m-5n>m^2\)? --> is \(m(4-m)>5n\)?
(1) n<0. Well this statement is clearly insufficient as we know nothing about \(m\), though from it we know that \(RHS=5n<0\) (RHS is negative).
(2) m is an integer between 0 and 4 inclusive. Insufficient because of the same reason: no info about \(n\), but again from this statement we know that the least value of \(LHS=m(4-m)\) is zero (when \(m=4\) or \(m=0\)) in all other cases \(LHS=m(4-m)>0\).
(1)+(2) \(LHS=m(4-m)\geq{0}\) and \(RHS<0\): \(m(4-m)>5n\). Sufficient.
Answer: C.
24 Dec 2017, 09:02
Kudos
Bookmarks
Is 4m - 5n > m^2 ?
(1) n is negative.
(2) m is an integer between 0 and 4, inclusive.
The answer is C
Statement 1 is insufficient as we do not know antthing about m it can be negative and positive
Suppose n=-1
and m=0
then 5>0 true but when m = -2 we have for the same value of n
-8+5> -2^2
-3>4 false
So statement 1 is insufficient
Statement 2 is also insufficient as we do know anything about n
suppose m=1 and n=0
4>1 true
now let us say m=4 then
16>16 no true hence insufficient .
Taken together they they are sufficient as
4m-5n>m^2
Let n=-1
4m+5>m^2
m=0 true when m=1 it is true
(1) n is negative.
(2) m is an integer between 0 and 4, inclusive.
The answer is C
Statement 1 is insufficient as we do not know antthing about m it can be negative and positive
Suppose n=-1
and m=0
then 5>0 true but when m = -2 we have for the same value of n
-8+5> -2^2
-3>4 false
So statement 1 is insufficient
Statement 2 is also insufficient as we do know anything about n
suppose m=1 and n=0
4>1 true
now let us say m=4 then
16>16 no true hence insufficient .
Taken together they they are sufficient as
4m-5n>m^2
Let n=-1
4m+5>m^2
m=0 true when m=1 it is true
