GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Feb 2019, 15:28

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
• ### Valentine's day SALE is on! 25% off.

February 18, 2019

February 18, 2019

10:00 PM PST

11:00 PM PST

We don’t care what your relationship status this year - we love you just the way you are. AND we want you to crush the GMAT!
• ### Get FREE Daily Quiz for 2 months

February 18, 2019

February 18, 2019

10:00 PM PST

11:00 PM PST

Buy "All-In-One Standard (\$149)", get free Daily quiz (2 mon). Coupon code : SPECIAL

# Is 4m - 5n > m^2

Author Message
TAGS:

### Hide Tags

Director
Joined: 07 Jun 2004
Posts: 589
Location: PA
Is 4m - 5n > m^2  [#permalink]

### Show Tags

25 Jan 2011, 05:51
00:00

Difficulty:

25% (medium)

Question Stats:

75% (01:59) correct 25% (01:55) wrong based on 128 sessions

### HideShow timer Statistics

Is 4m - 5n > m^2

(1) n < 0

(2) m is an integer between 0 and 4 inclusive
Math Expert
Joined: 02 Sep 2009
Posts: 52938

### Show Tags

25 Jan 2011, 06:01
1
rxs0005 wrote:
is 4m - 5n > m^2

1. n < 0

2. m is an integer between 0 and 4 inclusive

Is $$4m-5n>m^2$$? --> is $$m(4-m)>5n$$?

(1) n<0. Well this statement is clearly insufficient as we know nothing about $$m$$, though from it we know that $$RHS=5n<0$$ (RHS is negative).

(2) m is an integer between 0 and 4 inclusive. Insufficient because of the same reason: no info about $$n$$, but again from this statement we know that the least value of $$LHS=m(4-m)$$ is zero (when $$m=4$$ or $$m=0$$) in all other cases $$LHS=m(4-m)>0$$.

(1)+(2) $$LHS=m(4-m)\geq{0}$$ and $$RHS<0$$: $$m(4-m)>5n$$. Sufficient.

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 52938
Re: Is 4m - 5n > m^2  [#permalink]

### Show Tags

23 Feb 2014, 03:32
Bumping for review and further discussion.
_________________
SVP
Joined: 06 Sep 2013
Posts: 1695
Concentration: Finance
Re: Is 4m - 5n > m^2  [#permalink]

### Show Tags

22 Apr 2014, 06:24
My way

Is 4m-5n>m^2?

5n<4m-m^2
5n<n(4-m)?

Statement 1

n<0

Therefore, n(4-m)>0 given that n<0 thus is m>4?

Can't know this so insufficient

Statement 2

We are told that 0<m<4 but nothing else.

Insufficient

Statements 1 and 2 together

We have that m>4 is not possible since 0<m<4 therefore sufficient

C

Hope this helps
Cheers!
J
Current Student
Joined: 12 Aug 2015
Posts: 2621
Schools: Boston U '20 (M)
GRE 1: Q169 V154
Re: Is 4m - 5n > m^2  [#permalink]

### Show Tags

13 Mar 2016, 06:34
Superb Question...
Here after plotting possible values of m and n from statement 1 and 2 on the number line => One side LHS is always +ve and the other always -ve hence => C is sufficient
_________________
Director
Joined: 09 Mar 2018
Posts: 986
Location: India
Re: Is 4m - 5n > m^2  [#permalink]

### Show Tags

26 Jan 2019, 07:13
rxs0005 wrote:
Is 4m - 5n > m^2

(1) n < 0

(2) m is an integer between 0 and 4 inclusive

Never take assumptions

(1) n < 0
Insufficient, cant say anything about m

(2) m is an integer between 0 and 4 inclusive
Insufficient, cant say anything about n

Combine

Is 4m - 5n > m^2

This will always be true.
4m +5n > m^2, will become +ive and for the given values it will always be true.

C
_________________

If you notice any discrepancy in my reasoning, please let me know. Lets improve together.

Quote which i can relate to.
Many of life's failures happen with people who do not realize how close they were to success when they gave up.

Re: Is 4m - 5n > m^2   [#permalink] 26 Jan 2019, 07:13
Display posts from previous: Sort by