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devinawilliam83
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devinawilliam83
If a, b, and c are each positive integers greater than 1 is the product abc divisible by 6?

(1) The product ab is even
(2) The product bc is divisible by 3


1> \(a*b\) = an even integer
\(abc\)=even integer*(c)= an even integer. but are all even integers divisible by 6? nope. Not suff.

2>The product bc is divisible by 3.

bc is a multiple of 3 (let's denote bc=3q, q=1,2,3,4..)

thus, \(abc= 3q*a \)= any multiple of 3.

but are all multiples of 3 divisible by 6? nope.eg \(3*1=3\) which is not divisible by 6. but \(3*2=6\), which is divisible by 6. Not suff.

1+2 together. and Bunuel has already given the theory about what we can infer if a product is divisible by 2 and 3 then it MUST be divisible by 6 as well. Sufficient.
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for (1) : ab is even --> not sufficient
(2) --> also not sufficient

consider both (1) and (2)
ab is divisible by 2 so ab = 2 * ...
bc is divisible by 3 so bc = 3 * ...
this means that abc should be 6 * ... as it should have a component of 2 and 3
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