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05 Apr 2012, 13:25
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A
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Difficulty:
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87% (00:43) correct
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If x and y are positive, what is the value of x-y?
(1) (x^2 - y^2)/ (x + y) = 4
(2) x + y = 7
(1) (x^2 - y^2)/ (x + y) = 4
(2) x + y = 7
05 Apr 2012, 13:41
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If x and y are positive, what is the value of x-y?
(1) (x^2 - y^2)/ (x + y) = 4 --> \(\frac{(x- y)(x+y)}{x + y}= 4\) --> reduce by \(x+y\): \(x-y=4\). Sufficient.
(2) x + y = 7. Clearly insufficient.
Answer: A.
(1) (x^2 - y^2)/ (x + y) = 4 --> \(\frac{(x- y)(x+y)}{x + y}= 4\) --> reduce by \(x+y\): \(x-y=4\). Sufficient.
(2) x + y = 7. Clearly insufficient.
Answer: A.
General Discussion
30 Apr 2012, 11:22
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eybrj2
Ans Exp:
so we are required to find the difference between x and y
Statement 1: (x^2 - y^2)/ (x + y) = 4
by observing keenly we can get that the numerator i.e (x^2 - y^2) is in (a^2)-(b^2) so this can be written as
(a +b)(a-b) so
(x^2 - y^2)/ (x + y) = 4 => (x+y)(x-y)/(x+y)=4 =>by cancelling x+y in both numerator and denominator we are left with x-y=4 which is required ,so statement 1 is sufficient to answer the question .
Statement 2: x+y=7 as the question wanted us to solve for x-y we do nothing with x+y so statement 2 is insufficient
Answer = A.
