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13 May 2012, 08:11
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
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Question Stats:
58% (02:15) correct
42%
(02:00)
wrong
based on 131
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If P, Q, R are positive numbers such that R = 100P + 20Q, and P + Q = 2, is R < 120?
(1) P > 1.1
(2) P > Q
(1) P > 1.1
(2) P > Q
13 May 2012, 23:57
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R = 100P + 20Q, and P + Q = 2
Using statement (1), if P>1.1, Q<0.9
As R = 100P + 20Q, R is smallest when P is at its smallest and Q at its largest. This happens when P=1.11 and Q=0.89
R(min)= 100(1.11) + 20(0.89) = 111 + 17.8 which is greater than 120
Therefore R>120. Sufficient.
Using statement (2),
P>Q
R(min) = 100 (1.01) + 20(0.99) = 101 + 19.8 = which is more than 120. Sufficient.
D it is.
Using statement (1), if P>1.1, Q<0.9
As R = 100P + 20Q, R is smallest when P is at its smallest and Q at its largest. This happens when P=1.11 and Q=0.89
R(min)= 100(1.11) + 20(0.89) = 111 + 17.8 which is greater than 120
Therefore R>120. Sufficient.
Using statement (2),
P>Q
R(min) = 100 (1.01) + 20(0.99) = 101 + 19.8 = which is more than 120. Sufficient.
D it is.
14 May 2012, 07:52
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R=100(p) + 20(q), p+q=2,is R<120
after rephrasing:
R= 100(2-Q) +20(q)
R= 200-100(q)+20(q)
R= 200-80(q)
200-80(q)<120
200-120<80(q)
80<80(q)
Is 1<q or q>1
stmnt1) no info about q
stmnt2) not sufficient
(1+2) p>1.1,p>q
minimum value of p= 1.2 then q maybe 1.1 ( q>1 yielding yes)
q may be .75 ( q<1, yielding no)
whats wrong with my answer , plz explain
after rephrasing:
R= 100(2-Q) +20(q)
R= 200-100(q)+20(q)
R= 200-80(q)
200-80(q)<120
200-120<80(q)
80<80(q)
Is 1<q or q>1
stmnt1) no info about q
stmnt2) not sufficient
(1+2) p>1.1,p>q
minimum value of p= 1.2 then q maybe 1.1 ( q>1 yielding yes)
q may be .75 ( q<1, yielding no)
whats wrong with my answer , plz explain
