piyatiwari
I think the catch here is that the given equation is not equal to 0.
So this can have two differnt values based on two equations in statements.
Experts, correct me if I'm wrong.
the given equation is not equal to 0.An equation cannot be equal to 0. Equation is a statement. The statement is that two algebraic expressions are equal. The equality sign = is used between the two expressions, separating the two sides which should be equal. In particular, one of the sides can be 0. To distinguish it from an identity, which is true for any value of the variable (\(x\) in our case), an equation has a finite number of solutions, meaning that equality holds only for some specific values of the variable.
\(x+1=2x-x+1\) is and identity, it holds for any value of \(x.\)
\(x+3=5\) is an equation, this equality holds only for \(x=2.\) We say that 2 is a root of the equation or solution of the equation. You can solve by some method an equation and find the root(s), or if given a root, you can check if the specific number is indeed a root.
If I don't know how to solve the equation \(x+3=5\) but somebody tells me that \(2\) is a root of it, I can check by substituting \(2\) for \(x:\)
\(2+3=5\) it is indeed true, so \(2\) is a solution of the given equation. But if I don't know about methods of solving such equations or I cannot prove whether there might be additional solutions, I am in "trouble", as I cannot check all the real numbers to see whether there is another solution or not.
\(x^2+ 5x +4\) is an algebraic expression, not an equation. The value of this expression is determined by the particular value of \(x.\)
Obviously, for different values of \(x\) the expression can take different values. And once \(x\) is known, the value of the given expression is uniquely determined. That's why the answer to this question is D.