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06 Dec 2012, 06:23
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D
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Difficulty:
5%
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Question Stats:
90% (00:51) correct
10%
(01:09)
wrong
based on 1422
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What is the average (arithmetic mean) of j and k ?
(1) The average (arithmetic mean) of j + 2 and k + 4 is 11.
(2) The average (arithmetic mean) of j, k, and 14 is 10.
(1) The average (arithmetic mean) of j + 2 and k + 4 is 11.
(2) The average (arithmetic mean) of j, k, and 14 is 10.
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06 Dec 2012, 06:26
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What is the average (arithmetic mean) of j and k ?
We need to find the value of \(\frac{j+k}{2}\).
(1) The average (arithmetic mean) of j + 2 and k + 4 is 11 --> \(\frac{(j+2)+(k+4)}{2}=11\) --> \(j+k=16\). Sufficient.
(2) The average (arithmetic mean) of j, k, and 14 is 10 --> \(\frac{j+k+14}{3}=10\) --> \(j+k=16\). Sufficient.
Answer: D.
We need to find the value of \(\frac{j+k}{2}\).
(1) The average (arithmetic mean) of j + 2 and k + 4 is 11 --> \(\frac{(j+2)+(k+4)}{2}=11\) --> \(j+k=16\). Sufficient.
(2) The average (arithmetic mean) of j, k, and 14 is 10 --> \(\frac{j+k+14}{3}=10\) --> \(j+k=16\). Sufficient.
Answer: D.
21 Dec 2016, 17:33
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Nice official Question.
Here is my solution to this one =>
In order to get the mean => we need the sum j+k
Statement 1=>
j+k=22-6=16
Hence sufficient
Statement 2=>
j+k=30-14=16
Hence sufficient
Hence D
Here is my solution to this one =>
In order to get the mean => we need the sum j+k
Statement 1=>
j+k=22-6=16
Hence sufficient
Statement 2=>
j+k=30-14=16
Hence sufficient
Hence D
