piyushmnit
Can someone please explain why C is correct
Two sets, M and Q, include only consecutive multiples of 5 and only consecutive multiples of 10 as their members, respectively. Both sets M and Q contain more than one member each. Is the median of set Q more than the median of set M?(1) Set M contains two times as many elements as set Q. If M={5, 10, 15,
20, 25, 30, 35} and Q={0,
10, 20}, then the median of M (20) is greater than the median of Q (10) BUT if M={5, 10, 15,
20, 25, 30, 35} and Q={20,
30, 40}, then the median of M (20) is less than the median of Q (30). Not sufficient.
(2) The smallest element in either set is 20. If M={20, 25, 30,
35, 40, 45, 50} and Q={20,
30, 40}, then the median of M (35) is greater than the median of Q (30) BUT if M={20,
25, 30} and Q={20,
30, 40}, then the median of M (25) is less than the median of Q (30). Not sufficient.
(1)+(2) Set M contains two times as many elements as set Q AND the smallest element in either set is 20. This implies that the median of M always will be farther from 20 than the median of Q. Consider the examples:
M={20,
25, 30, 35} and Q={
20, 30};
M={20, 25,
30, 35, 40, 45} and Q={20,
30, 40};
M={20, 25, 30,
35, 40, 45, 50, 55} and Q={20,
30, 40, 45};
M={20, 25, 30, 35,
40, 45, 50, 55, 60, 65} and Q={20, 30,
40, 45, 50}.
Sufficient.
Answer: C.