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13 May 2013, 13:53
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
38% (02:06) correct
62%
(02:15)
wrong
based on 177
sessions
History
Date
Time
Result
Not Attempted Yet
If \(n= p^2-p+17\), is \(n\) prime?
1)\(p\) is prime
2)\(p\) is an integer less than \(17\)
Hi guys this is a question I just created. OE here
As always any feedback is appreciated
1)\(p\) is prime
2)\(p\) is an integer less than \(17\)
Hi guys this is a question I just created. OE here
As always any feedback is appreciated
Posts: 191
13 May 2013, 19:52
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Zarrolou
The correct answer is C.
A) If you pick p =17. Than n is not prime.
if you pick p=2. Than n is prime.
Insufficient.
B) From the above reasoning an integer less than 17 can be negative also.
If you take p=-17 than n is not prime. if you take p=2 than n is prime.
Hence , if you take both , then a prime number less than 17 will surely make n prime.
Hence, answer is C.
General Discussion
13 May 2013, 19:00
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N = p^2 - P + 17
N = P(P-1) + 17
Is N prime?
St1: P = Prime Number
if p = 2, 2*1 + 17 = 19 Prime
If p = 17, 17*16 + 17 = a multiple of 17. hence Not Prime
Insufficient
ST2: P = Integer < 17
True for all integers.
Product of any 2 consecutive integers + 17 will yield a prime number.
if p = 3, 3*2+17 = 23 (prime)
if p = 6, 6*5 + 17 = 47 (prime)
same for all integers less than 17.
SUFFICIENT
Ans B
N = P(P-1) + 17
Is N prime?
St1: P = Prime Number
if p = 2, 2*1 + 17 = 19 Prime
If p = 17, 17*16 + 17 = a multiple of 17. hence Not Prime
Insufficient
ST2: P = Integer < 17
True for all integers.
Product of any 2 consecutive integers + 17 will yield a prime number.
if p = 3, 3*2+17 = 23 (prime)
if p = 6, 6*5 + 17 = 47 (prime)
same for all integers less than 17.
SUFFICIENT
Ans B
