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Updated on: 19 Jun 2013, 14:39
Originally posted by atalpanditgmat on 15 Jun 2013, 00:57.
Last edited by Bunuel on 19 Jun 2013, 14:39, edited 3 times in total.
Last edited by Bunuel on 19 Jun 2013, 14:39, edited 3 times in total.
Edited the OA.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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60% (01:35) correct
40%
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If ax^2 + bx^3 = 5, where a and b are non-zero numbers, what is the value of a + b?
(1) ax^2 = a
(2) bx^3 = b
As per the 800score, it is .
(1) ax^2 = a
(2) bx^3 = b
As per the 800score, it is .
15 Jun 2013, 01:19
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The correct answer is neither C nor D. Please check OA.
If ax^2 + bx^3 = 5, where a and b are non-zero numbers, what is the value of a + b?
(1) ax^2 = a --> since \(a\) is non-zero reduce by it: \(x^2 = 1\) --> \(x = 1\) or \(x = -1\). If \(x = 1\), then \(a + b= 5\) but if \(x = -1\), then \(a - b = 5\), from which we cannot get the value of \(a+b\). Not sufficient.
(2) bx^3 = b --> since \(b\) is non-zero reduce by it: \(x^3 = 1\) --> \(x = 1\) --> \(ax^2 + bx^3 = 5\) becomes \(a + b= 5\). Sufficient.
Answer: B.
If ax^2 + bx^3 = 5, where a and b are non-zero numbers, what is the value of a + b?
(1) ax^2 = a --> since \(a\) is non-zero reduce by it: \(x^2 = 1\) --> \(x = 1\) or \(x = -1\). If \(x = 1\), then \(a + b= 5\) but if \(x = -1\), then \(a - b = 5\), from which we cannot get the value of \(a+b\). Not sufficient.
(2) bx^3 = b --> since \(b\) is non-zero reduce by it: \(x^3 = 1\) --> \(x = 1\) --> \(ax^2 + bx^3 = 5\) becomes \(a + b= 5\). Sufficient.
Answer: B.
