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B
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Difficulty:
25%
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Question Stats:
75% (01:25) correct
25%
(01:17)
wrong
based on 61
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Jenifer, David and Steve are children of Mrs. Noris .
How many children are there in Mrs. Noris's family?
(1) According to one ranking rendered by a renowned beauty expert , Maria is in the median position among her sisters regarding only beauty.
(2) David and Steve both have just only one brother and the range of total brother and total sister is Five.
How many children are there in Mrs. Noris's family?
(1) According to one ranking rendered by a renowned beauty expert , Maria is in the median position among her sisters regarding only beauty.
(2) David and Steve both have just only one brother and the range of total brother and total sister is Five.
statement 2:
let no. of sisters=x
no.of boys=2 as stated in this statement
range is 5
therefore x-2=5
x=7
total children = 7+2 =9
according to me...STATEMENT 2 is sufficient.
so Answer is (B)
let no. of sisters=x
no.of boys=2 as stated in this statement
range is 5
therefore x-2=5
x=7
total children = 7+2 =9
according to me...STATEMENT 2 is sufficient.
so Answer is (B)
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solution:
From statement(1), we can infer the total number of the sisters is an odd number.
if even then it would not be possible for Maria to be in the median position.
Ranking is not consist of fractions and neither the number of the sisters.
Such as the sisters' number can be 3 or 5 or 7 or 9 or 11 etc, but it must be an odd number,
so that Maria can take the middle place.
For example:
1 2(maria) 3 or 1 2 3 4(maria) 5 6 7 like these.
So statement (1) provide an important information but alone is not sufficient.
From statement (2), we can easily see that David has one brother and Steve has one brother too and they have just only one brother and they are also their brother.
It indicates that David and Steve are the only two sons in the family.
Further the statement (2) claims that the range of total brothers and total sisters is 5.
It means
number of sister - number of brothers = 5 (range is the difference between the highest and lowest number).
By combining both, we can evaluate the actual number of the sisters.
We know there are 2 brothers and the range is 5. so the number of sisters is 7 , because 7-2=5.
Finally we have 7 sisters and 2 brothers. so total 9 children...
Both together are sufficient.
Answer is (C) .
please express your valuable opinion.
Thanks everyone
this was my 1st answer and its flawed.
statement (2) alone is sufficient.
Answer (B)
From statement(1), we can infer the total number of the sisters is an odd number.
if even then it would not be possible for Maria to be in the median position.
Ranking is not consist of fractions and neither the number of the sisters.
Such as the sisters' number can be 3 or 5 or 7 or 9 or 11 etc, but it must be an odd number,
so that Maria can take the middle place.
For example:
1 2(maria) 3 or 1 2 3 4(maria) 5 6 7 like these.
So statement (1) provide an important information but alone is not sufficient.
From statement (2), we can easily see that David has one brother and Steve has one brother too and they have just only one brother and they are also their brother.
It indicates that David and Steve are the only two sons in the family.
Further the statement (2) claims that the range of total brothers and total sisters is 5.
It means
number of sister - number of brothers = 5 (range is the difference between the highest and lowest number).
By combining both, we can evaluate the actual number of the sisters.
We know there are 2 brothers and the range is 5. so the number of sisters is 7 , because 7-2=5.
Finally we have 7 sisters and 2 brothers. so total 9 children...
Both together are sufficient.
Answer is (C) .
please express your valuable opinion.
Thanks everyone
this was my 1st answer and its flawed.
statement (2) alone is sufficient.
Answer (B)
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05 Aug 2013, 11:29
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Asifpirlo
hi asif,
can you elaborate how statement 1 is useful .?
as per statement 2:
let no. of sisters=x
no.of boys=2 as stated in this statement
range is 5
therefore x-2=5
x=7
total children = 7+2 =9
according to me...STATEMENT 2 is sufficient.
