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21 Aug 2013, 17:56
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:40) correct
31%
(02:05)
wrong
based on 29
sessions
History
Date
Time
Result
Not Attempted Yet
A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?
(1) The average width of the limousines is the square root of x.
(2) x = 100.
(1) The average width of the limousines is the square root of x.
(2) x = 100.
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22 Aug 2013, 02:48
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Asifpirlo
Some assumptions to be made in this question...
When we combine we get that the width of limousines is 10 meters. Thus 9 limousines will need 9*10=90 meters, plus the additional space required between each two cars and between the cars and the walls. The sum will be more than 100 meters. So, the answer is NO. Sufficient.
Answer: C.
22 Aug 2013, 03:10
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Asifpirlo
x = 9 (Average width of Limo) + Min [10 (2)] -----(1)
10 because 9 cars will have 8 gaps & 2 gaps for extreme ends (between wall & car)
Statement 1
x = 9 \(\sqrt{x}\) + Min [10 (2)]
Still we cant solve the equation as we don't know the value of x
Thus insufficient
Statement 2
100 = 9 (Average width of Limo) + Min [10 (2)]
Still we cant solve the equation as we don't know the value of "Average width of Limo"
Thus insufficient
Statement 1&2
100 = 9 \(\sqrt{100}\) + Min [10 (2)]
100 = 9 (10) + Min [10 (2)]
100 = Min 110
This clearly shows the garage won't be able to hold all the 9 limos
Thus Sufficient
Answer C
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