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Image attached

We basically need the sides of the rectangle to calculate the area

STAT1: STAT1 by itself is not sufficient as we do not anything about the length of the rectangle to find the area.
Two possible cases (there can be many more) for the rectangle are shown in the image 1
So, INSUFFICIENT

STAT2: STAT2 by itself is not sufficient as longer side can be the base of the rectangle or can be the height. (image 2)
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, so Area = height * base = 12 * 12 * 1.5
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, we are getting two different values for Area
So, INSUFFICIENT

Taking both together
We will have the two cases (and similar cases with positive and negative values for x) as shown in Image 1

Now, the case with the rectangle with one edge on x-axis is straight forward
if you take the longer side as base then height/base = slope = 1.5 so, height = 1.5* base = 1.5 * 12 which is not possible as base was longer side, not the height
So, height is 12 and base will be height /slope = 12/1.5 = 8. So, Area will be 12* 8 = 96

Now, the case with the two diagonal vertices on x-axis
Now only possible case when the other diagonal will have a positive slope is in the second case of image 1. But this will not be possible as the smaller side will be 12 * 1.5, which is greater than the other side of the rectangle.

So, we will have only one case. So, SUFFICIENT.

So, Answer will be C
Hope it helps!

desaichinmay22
What is the area of rectangle ABCD?

(1) Two of the vertices of rectangle ABCD lie on the X-axis

(2) The longer side of the rectangle measures 12 cms and one of the diagonals has a slope of 1.5

Please help me understand below point :

I have highlighted some portion from your solution. If assumption is that longer side is base then how can height be base*slope (we already know slope is > 1). Initially I chose B only since I couldn't think of any other combination of l*b except (12*8)

STAT2: STAT2 by itself is not sufficient as longer side can be the base of the rectangle or can be the height. (image 2)
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, so Area = height * base = 12 * 12 * 1.5
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, we are getting two different values for Area
So, INSUFFICIENT
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I did a mistake there, i will change it.
The answer should be B right? We know that the longer side is 12 and doesn't matter how we draw the rectangle we know that the slope of one diagonal is 1.5 and the height for that slope (if we talking in terms of tan theta) will be 12 and base will be 12/1.5, which is 8 right? What else can we draw anyways?
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nktdotgupta
Image attached

We basically need the sides of the rectangle to calculate the area

STAT1: STAT1 by itself is not sufficient as we do not anything about the length of the rectangle to find the area.
Two possible cases (there can be many more) for the rectangle are shown in the image 1
So, INSUFFICIENT

STAT2: STAT2 by itself is not sufficient as longer side can be the base of the rectangle or can be the height. (image 2)
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, so Area = height * base = 12 * 12 * 1.5
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, we are getting two different values for Area
So, INSUFFICIENT

Taking both together
We will have the two cases (and similar cases with positive and negative values for x) as shown in Image 1

Now, the case with the rectangle with one edge on x-axis is straight forward
if you take the longer side as base then height/base = slope = 1.5 so, height = 1.5* base = 1.5 * 12 which is not possible as base was longer side, not the height
So, height is 12 and base will be height /slope = 12/1.5 = 8. So, Area will be 12* 8 = 96

Now, the case with the two diagonal vertices on x-axis
Now only possible case when the other diagonal will have a positive slope is in the second case of image 1. But this will not be possible as the smaller side will be 12 * 1.5, which is greater than the other side of the rectangle.

So, we will have only one case. So, SUFFICIENT.

So, Answer will be C
Hope it helps!

desaichinmay22
What is the area of rectangle ABCD?

(1) Two of the vertices of rectangle ABCD lie on the X-axis

(2) The longer side of the rectangle measures 12 cms and one of the diagonals has a slope of 1.5

Please help me understand below point :

I have highlighted some portion from your solution. If assumption is that longer side is base then how can height be base*slope (we already know slope is > 1). Initially I chose B only since I couldn't think of any other combination of l*b except (12*8)

STAT2: STAT2 by itself is not sufficient as longer side can be the base of the rectangle or can be the height. (image 2)
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, so Area = height * base = 12 * 12 * 1.5
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, we are getting two different values for Area
So, INSUFFICIENT
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I chose B as answer, but OA was given as C. I don't have OE for this problem. We need expert's opinion.

Bunuel :- Request you to provide solution for given problem.
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nktdotgupta
Image attached

We basically need the sides of the rectangle to calculate the area

STAT1: STAT1 by itself is not sufficient as we do not anything about the length of the rectangle to find the area.
Two possible cases (there can be many more) for the rectangle are shown in the image 1
So, INSUFFICIENT

STAT2: STAT2 by itself is SUFFICIENT as doesn't matter however we draw the rectangle we can always find the vertices
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, which is not possible as the longer side is 12, so this side cannot be longer than 12
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, SUFFICIENT

I think answer should be B?

desaichinmay22
What is the area of rectangle ABCD?

(1) Two of the vertices of rectangle ABCD lie on the X-axis

(2) The longer side of the rectangle measures 12 cms and one of the diagonals has a slope of 1.5

For (2) consider the following case:
Attachment:
Untitled.png
Untitled.png [ 12.65 KiB | Viewed 4284 times ]
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Thanks Bunuel. I drew this case in my image 1 part 2 but took theta wrong :)
Bunuel
nktdotgupta
Image attached

We basically need the sides of the rectangle to calculate the area

STAT1: STAT1 by itself is not sufficient as we do not anything about the length of the rectangle to find the area.
Two possible cases (there can be many more) for the rectangle are shown in the image 1
So, INSUFFICIENT

STAT2: STAT2 by itself is SUFFICIENT as doesn't matter however we draw the rectangle we can always find the vertices
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, which is not possible as the longer side is 12, so this side cannot be longer than 12
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, SUFFICIENT

I think answer should be B?

desaichinmay22
What is the area of rectangle ABCD?

(1) Two of the vertices of rectangle ABCD lie on the X-axis

(2) The longer side of the rectangle measures 12 cms and one of the diagonals has a slope of 1.5

For (2) consider the following case:
Attachment:
Untitled.png
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nktdotgupta
Thanks Bunuel. I drew this case in my image 1 part 2 but took theta wrong :)

Yes, theta is an angle between the diagonal and x-axis, not the diagonal and the side of the rectangle.
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nktdotgupta
Image attached

We basically need the sides of the rectangle to calculate the area

STAT1: STAT1 by itself is not sufficient as we do not anything about the length of the rectangle to find the area.
Two possible cases (there can be many more) for the rectangle are shown in the image 1
So, INSUFFICIENT

STAT2: STAT2 by itself is SUFFICIENT as doesn't matter however we draw the rectangle we can always find the vertices
If the longer side is base then while using : tan (theta) = slope = height/base we will have height = base * slope = 12 * 1.5, which is not possible as the longer side is 12, so this side cannot be longer than 12
If the longer side is height then while using : tan (theta) = slope = height/base we will have base = height / slope = 12 / 1.5, so Area = height * base = 12 * 12 / 1.5
So, SUFFICIENT

I think answer should be B?

desaichinmay22
What is the area of rectangle ABCD?

(1) Two of the vertices of rectangle ABCD lie on the X-axis

(2) The longer side of the rectangle measures 12 cms and one of the diagonals has a slope of 1.5

For (2) consider the following case:
Attachment:
Untitled.png


Bunuel: Hello sir, i have a query ...How come you are considering thr equation of the line as y=mx........... It can be also of the form Y=mX +c..............
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Bunuel: Hello sir, i have a query ...How come you are considering thr equation of the line as y=mx........... It can be also of the form Y=mX +c..............

In my post I showed why the second statement is not sufficient by drawing two rectangles with different areas. You are right, the diagonal could be on any line with the slope 3/2, so it's on the line y = 3/2*x + c. I just showed two rectangles with two different areas having their diagonals on y = 3/2*x (one of many possibilities), which is enough to prove insufficiency.
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