Bunuel
Tough and Tricky questions: Word Problems.
Last season, the Rally Cats won 40 percent of the first 45 games they played. Assuming there were no ties, the Rally Cats won what percent of all the games they played last season?
(1) The Rally Cats won 1/2 of their remaining games last season (after the first 45 games).
(2) The Rally Cats won 50 games in total last season.
Kudos for a correct solution. OFFICIAL SOLUTION:We know that the Rally Cats won 40% of their first 45 games. So the number of games won in the first 45 was:0.4 × 45 = 18.
Statement (1) tells us that they won 50% of their remaining games, but since we don't know how many games they played after the first 45, we don't know how many games they played in all or how many they won. This statement is insufficient.
Statement (2) tells us they won 50 games in all. Since they won 18 games in the first 45, the number of games they won in the rest of the season must have been:50 – 18 = 32.But since we don't know how many games they played in all, we can't determine what percent they won.
Combining the two statements, we know that the Rally Cats won 32 games in the remainder of the season, representing 50% of their remaining games.
So (.5)(remaining games) = 32.
Remaining games = 32/.5 = 64.
Now, we know how many games the Rally Cats played in all (45 + 64 = 109) and how many they won (50). To determine what percent they won, we could divide 50 by 109, so the statements combined are sufficient.
Since the statements are insufficient by themselves, but sufficient when combined, the correct answer is choice (C).