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Bunuel

Tough and Tricky questions: Word Problems.



Last season, the Rally Cats won 40 percent of the first 45 games they played. Assuming there were no ties, the Rally Cats won what percent of all the games they played last season?

(1) The Rally Cats won 1/2 of their remaining games last season (after the first 45 games).
(2) The Rally Cats won 50 games in total last season.

Kudos for a correct solution.

Total games won in firs 45 games = 40% = 18

The information we need is total number of games played and total wins

1. from this we get the percentage of games won after 45 games but we dont know total games or total wins - In sufficient
2. From this we know total wins as 50 but no information about total games played - Not Sufficient

Combining both:

Total wins = 50 ---- from Statement 1
wins after 45th match = 50-18 = 32
games played after 45th match = 32*2 = 64 --- from statement 2

Solving this we can get percentage

Ans C
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Last season, the Rally Cats won 40 percent of the first 45 games they played. Assuming there were no ties, the Rally Cats won what percent of all the games they played last season?

(1) The Rally Cats won 1/2 of their remaining games last season (after the first 45 games).
(2) The Rally Cats won 50 games in total last season.

From statement 1 we don't know the number of remaining games (it could be 30, 45 or 50 etc). Not sufficient
From statement 2 we only know that Cats won 32 out of all remaining games but nothing is known about number of games
1+2 together. Sufficient. We are told that 32=(1/2)x where x is a number of games left to play. Hence x=64
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We are given the team won 40% of 45 gives lets assume that to be x. We need not calculate how many.

S1 gives us that the team won half of the remaining games and call that number y. But we do not know what were total number of games. Hence this number can be anything. Thus Not sufficient.

S2 Tell us us that that the team won total of 50 games. But we do not know that how many games did the team play. so this is not sufficient.

Combining we will get the equation x+y=50 . Since we already know the the value of x we will get value of y. Adding y to 45 will give us total number of games played.

Thus answer is C.
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Bunuel

Tough and Tricky questions: Word Problems.



Last season, the Rally Cats won 40 percent of the first 45 games they played. Assuming there were no ties, the Rally Cats won what percent of all the games they played last season?

(1) The Rally Cats won 1/2 of their remaining games last season (after the first 45 games).
(2) The Rally Cats won 50 games in total last season.

Kudos for a correct solution.

OFFICIAL SOLUTION:

We know that the Rally Cats won 40% of their first 45 games. So the number of games won in the first 45 was:0.4 × 45 = 18.

Statement (1) tells us that they won 50% of their remaining games, but since we don't know how many games they played after the first 45, we don't know how many games they played in all or how many they won. This statement is insufficient.

Statement (2) tells us they won 50 games in all. Since they won 18 games in the first 45, the number of games they won in the rest of the season must have been:50 – 18 = 32.But since we don't know how many games they played in all, we can't determine what percent they won.

Combining the two statements, we know that the Rally Cats won 32 games in the remainder of the season, representing 50% of their remaining games.

So (.5)(remaining games) = 32.
Remaining games = 32/.5 = 64.

Now, we know how many games the Rally Cats played in all (45 + 64 = 109) and how many they won (50). To determine what percent they won, we could divide 50 by 109, so the statements combined are sufficient.

Since the statements are insufficient by themselves, but sufficient when combined, the correct answer is choice (C).
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