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Bunuel
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Bunuel
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Statement 1: P(T at least once in N trials)

case one n=4:

T occurs once . So it will be=1/4*3/4*3/4*3/4= 27/256.

T occurs twice so it will be= 1/4*1/4*3/4*3/4 = 9/256

T occurs three times so it will be= 1/4*1/4*1/4*3/4 = 3/256

T occurs four times so it will be= 1/4*1/4*1/4*1/4 = 1/256

so the sum = 27+9+3+1/256 = 40/256 <1/2 and the answer will be always less than 1/2 as we move to big number

5,6,7,..........so on. Statement 1 is suff

Statement 2: N could be 1,2,3,4,5

case one N=1 T occurs once = 1/4 <1/2

case 2 N=2

T occurs once= 1/4*3/4= 3/16
T occurs twice=1/4*1/4=1/16. So, 1/16+3/16= 4/16 = 1/8<1/2
case 3 N=3
T occurs once= 1/4*3/4*3/4= 9/64
T occurs twice=1/4*1/4*3/4= 3/64
T occurs tree times 1/4*1/4*1/4= 1/64. So, 9+3+1/64= 13/64<1/2
and so on the case for N=4,5 so statment 2 is also suff.
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Hi 23a2012,

When dealing with these types of probability questions, you have to consider ALL of the various ways that an outcome can occur.

Here, we know that the probability of Outcome T is 1/4 (so the probability of it NOT happening is 3/4)

If we run the experiment 2 times, the probability of Outcome T happening AT LEAST ONCE can be solved in 2 ways:

1) Figure out that probability that it does not happen at all and subtract that from the number 1
2) Figure out ALL of the various ways to get AT LEAST ONE Outcome T.

If you take the second approach, then you have to calculate each of these options:
1) Outcome on the first, NOT on the second.
2) Outcome on the second, NOT on the first.
3) Outcome on the first, Outcome on the second.

In your explanation, the individual calculations that you did were correct, BUT you did NOT consider all of the possibilities, so your overall calculation is incorrect.

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Bunuel
In a single Epsilon trial, the probability of Outcome T is 1/4. Suppose a researcher conducts a series of n independent Epsilon trials. Let P = the probability that Outcome T occurs at least once in n trials. Is P > 1/2?

(1) n > 3
(2) n < 6


Kudos for a correct solution.

Use the concept of 1-probability of not obtaining outcome T to account for all possibilities to included the order of success/failure.

Statement 1:
1-probability of not obtaining outcome T
1-(3/4)^4
1-(3/4)^5
The probability is always less than half when n is larger than 3
Sufficient

Statement 2:
when n is less than 6, the probability is less than 1/2 when n is 2 and the probability is greater than 1/2 when n is 3.
Insufficient

Answer: A
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