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Hi

The pic attached explains
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Bunuel

Points P, Q, R, S, and T all lie on the same line. The larger circle has center S and passes through P and T. The smaller circle has center R and passes through Q and S. What is the ratio of the area of the larger circle to the area of the smaller circle?

(1) ST:PQ = 5/2
(2) RT:PR = 13/7


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MAGOOSH OFFICIAL SOLUTION:

Call the radius of the larger circle y, and y = PS = ST. Call the radius of the smaller circle x, and x = RS = RQ. If we took a ratio of the areas, the factors of pi would cancel and we would be left with the ratio (y/x) squared. If we could solve for this simpler ratio, y/x, then we could find the ratio of areas.

Statement #1: ST = y and PQ = y – 2x, so
Attachment:
cpotg_img17.png
cpotg_img17.png [ 5.19 KiB | Viewed 10567 times ]
This allows us to solve for the ratio y/x, which would allow us to find the ratio of areas. This statement, alone and by itself, is sufficient.

Statement #2: RT = y + x and PR = y – x, so
Attachment:
cpotg_img18.png
cpotg_img18.png [ 1.64 KiB | Viewed 10516 times ]
Cross-multiply.
Attachment:
cpotg_img19.png
cpotg_img19.png [ 2.75 KiB | Viewed 10506 times ]
This allows us to solve for the ratio y/x, which would allow us to find the ratio of areas. This statement, alone and by itself, is sufficient.

Answer = (D)
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