Bunuel

Points P, Q, R, S, and T all lie on the same line. The larger circle has center S and passes through P and T. The smaller circle has center R and passes through Q and S. What is the ratio of the area of the larger circle to the area of the smaller circle?
(1) ST:PQ = 5/2
(2) RT:PR = 13/7
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:Call the radius of the larger circle y, and y = PS = ST. Call the radius of the smaller circle x, and x = RS = RQ. If we took a ratio of the areas, the factors of pi would cancel and we would be left with the ratio (y/x) squared. If we could solve for this simpler ratio, y/x, then we could find the ratio of areas.
Statement #1: ST = y and PQ = y – 2x, so
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This allows us to solve for the ratio y/x, which would allow us to find the ratio of areas. This statement, alone and by itself, is sufficient.
Statement #2: RT = y + x and PR = y – x, so
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Cross-multiply.
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cpotg_img19.png [ 2.75 KiB | Viewed 10510 times ]
This allows us to solve for the ratio y/x, which would allow us to find the ratio of areas. This statement, alone and by itself, is sufficient.
Answer = (D)