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13 Dec 2015, 05:54
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
56% (02:15) correct
44%
(02:27)
wrong
based on 385
sessions
History
Date
Time
Result
Not Attempted Yet
A souvenir shop made $ 2,400 in revenue selling postcards. If a large postcard costs twice as much as a small postcard, the shop sold 950 large postcards, and it sold no other type of postcard besides these two sizes, then how many small postcards did it sell?
(1) A large postcard costs $ 2.
(2) If the shop had sold 20% fewer small postcards, its revenue would have been reduced by 4 1/6 %.
(1) A large postcard costs $ 2.
(2) If the shop had sold 20% fewer small postcards, its revenue would have been reduced by 4 1/6 %.
14 Dec 2015, 11:10
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Given:
Revenue - $ 2400
No of large postcards - 950
No of small postcards - x
Cost of large postcard = 2* Cost of small postcard
Statement 1
Cost of Large postcard = $2
Cost of Small postcard = $1
950*2+x*1=2400
x=500 ---- Sufficient
Statement 2
Let the Cost of small postcard = y
New revenue is reduced by = 100
No of new post cards = 0.8x
950*2y+0.8yx=2300---(1)
950*2y+yx=2400---- (2) (given)
(1)- (2)
yx=500
y=1 and x=500
Sufficient
Hence , D
Revenue - $ 2400
No of large postcards - 950
No of small postcards - x
Cost of large postcard = 2* Cost of small postcard
Statement 1
Cost of Large postcard = $2
Cost of Small postcard = $1
950*2+x*1=2400
x=500 ---- Sufficient
Statement 2
Let the Cost of small postcard = y
New revenue is reduced by = 100
No of new post cards = 0.8x
950*2y+0.8yx=2300---(1)
950*2y+yx=2400---- (2) (given)
(1)- (2)
yx=500
y=1 and x=500
Sufficient
Hence , D
15 Dec 2015, 04:26
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
A souvenir shop made $ 2,400 in revenue selling postcards. If a large postcard costs twice as much as a small postcard, the shop sold 950 large postcards, and it sold no other type of postcard besides these two sizes, then how many small postcards did it sell?
(1) A large postcard costs $ 2.
(2) If the shop had sold 20% fewer small postcards, its revenue would have been reduced by 4 1/6 %.
When it comes to a question like the above, the question is frequently given in the Gmat Math test, which is "2 by 2" like the table below.
GCDS Bunuel A souvenir shop made (20151215).jpg [ 24.83 KiB | Viewed 5963 times ]
In this question, there are 4 variables(a,b,c,d) and 3 equations(b=2a, b=950, and ca+db=2,400), which should match with the number of equations. So, you need 1 more equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer.
1) c=2 is unique, which is sufficient.
2) c(0.8a)+db=2,400(1-4 1/6 %) is sufficient, which is sufficient. Therefore, the answer is D.
-> For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
A souvenir shop made $ 2,400 in revenue selling postcards. If a large postcard costs twice as much as a small postcard, the shop sold 950 large postcards, and it sold no other type of postcard besides these two sizes, then how many small postcards did it sell?
(1) A large postcard costs $ 2.
(2) If the shop had sold 20% fewer small postcards, its revenue would have been reduced by 4 1/6 %.
When it comes to a question like the above, the question is frequently given in the Gmat Math test, which is "2 by 2" like the table below.
Attachment:
GCDS Bunuel A souvenir shop made (20151215).jpg [ 24.83 KiB | Viewed 5963 times ]
1) c=2 is unique, which is sufficient.
2) c(0.8a)+db=2,400(1-4 1/6 %) is sufficient, which is sufficient. Therefore, the answer is D.
-> For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
