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(1) 9 < 3x < 15
=> 3< x < 5
Not sufficient as x can take non integer values between 3 and 5

(2) x/2 is an even integer
x= x/2 * 2 = even * even = even
=> x is even integer
Not sufficient

Combining 1 and 2 , we get
x=4

Answer C
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Bunuel
What is the value of x?

(1) 9 < 3x < 15
(2) x/2 is an even integer


Kudos for correct solution.

Statement 1: 9 < 3x < 15
3 < x <5
Insufficient

Statement 2:
x/2 is even
Clearly insufficient

Combining Statement 1 and 2:
The only even integral value between 3 and 5 is 4
Sufficient

Option C
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

What is the value of x?

(1) 9 < 3x < 15
(2) x/2 is an even integer


In the original condition, there is 1 variable(x), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer.
For 1), 3<x<5 -> x=4,4.1...., which is not unique and not sufficient.
For 2), x/2=even, x=2even=multiple of 4=4,8.., which is not unique and not sufficient.
When 1) & 2), x=4, which is unique and sufficient.
Therefore, the answer is C.


 For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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(1) 9 < 3x < 15
=> 3< x < 5
Not sufficient as x can take non integer values between 3 and 5

(2) x/2 is an even integer
x= x/2 * 2 = even * even = even
=> x is even integer
Not sufficient

Combining 1 and 2 , we get
x=4
CORRECT ANSWER C
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