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21 Mar 2016, 18:29
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
50% (02:09) correct
50%
(02:30)
wrong
based on 76
sessions
History
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Not Attempted Yet
Attachment:
Square aabb.jpg [ 8.15 KiB | Viewed 2732 times ]
1) (a+b)^2=49
2) (a^2)+(b^2)=25
* A solution will be posted in two days.
21 Mar 2016, 22:15
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Area of square = 20^2 = 400
Area of top triangle enclosed by length a = 0.5 * a^2
Area of the bottom triangle enclosed by length b = 0.5 * b^2
Area of shaded region = 400 - 0.5(a^2 + b^2)
St1: (a + b)^2 = 49 --> a^2 + b^2 + 2ab = 49 --> Not sufficient as we do not know the value of 2ab
St2: Clearly sufficient.
Answer: B
Area of top triangle enclosed by length a = 0.5 * a^2
Area of the bottom triangle enclosed by length b = 0.5 * b^2
Area of shaded region = 400 - 0.5(a^2 + b^2)
St1: (a + b)^2 = 49 --> a^2 + b^2 + 2ab = 49 --> Not sufficient as we do not know the value of 2ab
St2: Clearly sufficient.
Answer: B
23 Mar 2016, 18:44
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
If a square with 20 as one side’s length and decreases to a and b shown as above figure, what is the area of the region shaded?
1) (a+b)^2=49
2) (a^2)+(b^2)=25
When you modify the original condition and the question, 20^2-(a^2/2)-(b^2/2)=400-(a^2+b^2)/2 is derived, which makes 2) sufficient.
Thus, B is the answer.
If a square with 20 as one side’s length and decreases to a and b shown as above figure, what is the area of the region shaded?
1) (a+b)^2=49
2) (a^2)+(b^2)=25
When you modify the original condition and the question, 20^2-(a^2/2)-(b^2/2)=400-(a^2+b^2)/2 is derived, which makes 2) sufficient.
Thus, B is the answer.
