Solution:Given: r, s and t are different single digit positive integer, “ab” is defined as 2 digit integer. It can be written as \(“10 ×a+b+1".\)
To find: The value of “t”.
Analysis of statement 1: The product of s and (rs) is (st)We can do this problem by substituting the values ;
Case 1: Let s = 3 and r = 1; we get
\(s ×(10 ×r+s)=(10 ×s+ t)\)
\(3 ×(10 ×1+3)=(10 ×3+9)\)
Case 2: Let s = 2 and r = 1; we get
\(s ×(10 ×r+s)=(10 ×s+ t)\)
\(2 ×(10 ×1+2)=(10 ×2+4)\)
Looking at the above cases, it’s clear that, \(t = s^2\), as we can have many values for “s”, so we cannot determine the value of “t” as well. So statement 1 is not sufficient to answer. We can eliminate options A and D.
Analysis of statement 2: The sum of s and (rs) is (rt)We can do this problem by substituting the values ;
Case 1: Let s = 3 and r = 1; we get
\(s+(10 ×r+s)=(10 ×r+t)\)
\(3+(10 ×1+3)=(10 ×1+6)\)
Case 2: Let s = 2 and r = 1; we get
\(s+(10 ×r+s)=(10 ×r+t)\)
\(2+(10 ×1+2)=(10 ×1+4)\)
Looking at the above cases, it’s clear that, \(t = 2s\), as we can have many values for “s”, so we cannot determine the value of “t” as well.
So statement 2 is not sufficient to answer. We can eliminate option B.
Combining both the statements together; we get:From statement 1: \(t = s^2\)
From statement 2: \(t = 2s\)
This is true only when, s = 2; therefore t = 4.
So, the correct answer option is “C”.