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Bunuel
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Thanks for pointing out the error, vyshak. Corrected the solution!
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Bunuel
If n is a positive integer is n + 4 divisible by 8?

(1) n + 12 is divisible by 8

(2) n is divisible by 6

Given x > 0

Is \(\frac{(n + 4)}{8}\) = Integer?

Values n can have are 4, 12, 24, 36 etc.

Statement 1:\(\frac{(n+12)}{8}\) = Integer

Values n can take are 4, 12, 24, 36 etc (SUFFICIENT)

Statement 2: \(\frac{n}{6}\) = Integer

Values n can take are 6, 12, 18, 24 etc.

If n = 6, then answer to the question is NO i.e., n+4 is not divisible by 8

If n = 12, then then answer to the question is YES i.e., n+4 is divisible by 8

So NOT SUFFICIENT

So (A)
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Bunuel
If n is a positive integer is n + 4 divisible by 8?

(1) n + 12 is divisible by 8

(2) n is divisible by 6


from 1

n = 8p-12 Thus , n+4 = 8p - 8 , i.e. n+4 is divisible by 8 .... suff

from 2

n = 6k , thus n+4 = 6k+4 ... depends on K .. insuff

A
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