stonecold
If x,y,z are different prime numbers. What is the value of y?
1)xy is even
2)yz is even
Target question: What is the value of y? Given: x,y,z are different prime numbers. Statement 1: xy is even Let's TEST some values.
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 2 and y = 3. Here xy = (2)(3) = 6, which is even. In this case
y = 3Case b: x = 2 and y = 5. Here xy = (2)(5) = 10, which is even. In this case
y = 5Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: yz is even Let's TEST some values.
There are several values of y and z that satisfy statement 2. Here are two:
Case a: y = 3 and z = 2. Here yz = (3)(2) = 6, which is even. In this case
y = 3Case b: y = 2 and z = 3. Here yz = (2)(3) = 6, which is even. In this case
y = 2Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined If a product of two prime numbers is even, we can be certain that one of those prime number is 2 (since 2 is the only even prime)
So, from statement 1, we can conclude that either x or y is equal to 2.
From statement 2, we can conclude that either y or z is equal to 2.
When we combine the statements, the only possibility is that y = 2
Why is this? Well, we're told that x, y, and z are
different prime numbers. So, we can't have one value (x or y) equal 2 in statement 1, and then have have different value (y or z) equal 2 in statement 2.
So,
y must equal 2Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer:
Cheers,
Brent