In a certain mixture of juice and water, if only water was added to th

Question

In a certain mixture of juice and water, if only water was added to the mixture, how much water was added to the mixture?

(1) After adding water, water made up fifteen percent of the mixture.
(2) Before adding water, water made up ten percent of the mixture.

saswata4s · Answer

(1) & (2) alone are clearly insufficient.

(1) & (2) together: 
We have before adding water, water was 10% 
After adding water it was 15% of the mixture

Suppose the mixture was 100 litres initially.

So the water was 10 litres and remaining mixture was 90 litres.
After adding 6 litres of water, the mixture was 106 litres which has approximately 15% of water (16 litres).

Again suppose the mixture was 200 litres.
In that case, the water will be 20 litres and remaining mixture will be 180 litres.
And after adding 12 litres of water, the water will be approximately 15% of the mixture.

Therefore, we can deduce multiple scenarios if none of the actual quantities was mentioned.
Hence Insufficient. Answer E.

AMahmoodi · Answer

if there is T liter os mixture and it is W liter water then we add X liter of water to it we want x?

st1. W+X/T+X=.15 ---> we can't solve for x. insufficient.

st2. W/T=.1 ---> we cant find x . insuff.

st 1+2. from 2 we have W=.1T the put it in st1 equation we get .1T+X/T+X=.15 ---> yet impossible to solve for X . therefore E.

TheNightKing · Answer

Because both statements provide percentages but the question stem is asking quantity, the answer will be straight E.

Imagine this. First water was 10% now it is 15% unless I tell you the original base value you can never find out the new value. You can assume the base value to be 10l, 100l, 1000l. Everything will work.

Hence E.

rounakkedia172 · Answer

each of the two statements by itself is clearly insufficient, however lets combine them together to form some equations:

Let the initial amount of mixture be X:
We have, lets say the other component is Orange, Orange = 0.90x and water is 0.1x.

Now, adding some amount of water, this is what we are asked to find, lets call it Y
this contains 100% water.

in the final mixture, 
Orange = 0.85(x+y)
Water = 0.15(x+y)

We can equate the orange ratios as the volume of orange juice remains same:
0.9x = 0.85 (x+y)
X/y = 17/1

Now any combination of this ratio is acceptable, so infinite values of Y, hence E.

CEdward · Answer

I thought about this algebraically.

St1/St2 are clearly insufficient.

Well what about combined?

x 100 = 15
  x 100 = 10

2 Equations with 3 unknowns. Not solvable.

Answer is E.

solutaearum · Answer

A C trap problem:

(1) After adding water, water 15% of the mixture.
But we are not given initial Water or juice percentage they can be as low as 1% to as high as 99%
So we cannot determine much water was added to the mixture
 Not sufficient

(2) Before adding water, water made up ten percent of the mixture.
Now given that before water was 10% and juice was 90%.
Do not bring the Option 1 information to Option 2:

We don't know the amount of solution and amount of water that was added. 
 Not sufficient

Combining 1 & 2

We still don't know the amount of solution and amount of water that was added. 
We only know the percentage
 So we cannot determine much water was added to the mixture

Correct Option: E

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