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MathRevolution
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John and Tom leave the school at the same time to each of their houses. Does John reach his house faster than Tom?

1) The distance between the school and John’s house is 10km farther than the distance between the school and Tom’s house
2) Tom’s speed is 80% of John’s speed.

Got it incorrect, selected C, as I rushed instead of checking what the data may imply.

The data when combined still gives us two variables.
Time taken by John = D/S = [t +10/ 1.25s] (where t = distance of Tom’s house from school, and s = speed of Tom)
Time taken by Tom = D/S = t/s.

Therefore, we cannot produce a unique solution with 2 variables.
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Combining two statements ... I reached till below point.

Is x=X/0.8Y > X+10/Y .. where Y is speed of John and X is the Distance from School to house for tom.
For any positive values of X and Y the Lhs will be lower than RHS of the above eqn.

Where i am Wrong ???
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Hi, I think the question should be fixed. The question asks if Jhon reaches his house faster than Tom. In this sense, it doesn´t matter who arrives first, what the question is asking is who walked faster. Statement 2 should be sufficient to answer this. On the other hand, if the question asked who arrived first or earlier it would make sense that option E be correct. Please let me know if you see any flaw in this and thank you!
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