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getzgetzu
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Division R of Company Q has 1,000 employees. What is the average (arit 01 Dec 2005, 00:34
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E
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Division R of Company Q has 1,000 employees. What is the average (arithmetic mean) annual salary of the employees at Company Q?

(1) The average annual salary of the employees in Division R is $30,000.
(2) The average annual salary of the employees at Company Q who are not in Division R is $35,000.
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E
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pmenon
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Division R of Company Q has 1,000 employees. What is the average (arit 02 Apr 2009, 17:32
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Yes, E for me as well. C is the trap answer because it makes you think that since you have the two averages, you know the overall average.

Dont forget though that you need to know the total # of employees to determine overall average, which neither of the statements allow to us to deduce.
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GMATT73
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Division R of Company Q has 1,000 employees. What is the average (arit 01 Dec 2005, 09:15
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We do not know the total number of employees in the company.

Therefore, (E)
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Division R of Company Q has 1,000 employees. What is the average (arit 15 Oct 2008, 01:48
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cant we just add both averages together and then divide over 2? i know it´s a stupid question but pls guys be so kind and tell me logically why not :-)

thank you
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Division R of Company Q has 1,000 employees. What is the average (arit 15 Oct 2008, 02:29
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domleon
cant we just add both averages together and then divide over 2? i know it´s a stupid question but pls guys be so kind and tell me logically why not :-)

thank you
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No. That cannot be done. Check the following.

if total employees of division A is x1 and total salary is s1 then average = s1/x1.
If rest of employees is x2 and total salary of these is s2 then average = s2/x2.

Sum of the two averages = (s1/x1) + (s2/x2).

However, average at the company level = (s1+s2)/(x1+x2) and this is not the same as (s1/x1) + (s2/x2).

I hope, this helps.
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Division R of Company Q has 1,000 employees. What is the average (arit 24 Mar 2010, 15:25
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We can express the average annual salary of Company Q as:

\(S = \frac{S_r * N_r+ S_{not-r}*N_{not-r}}{N_r+N_{not-r}}\)

where
- \(S_r\) - The average annual salary of the employees in Division R
- \(S_{not-r}\) - The average annual salary of the employees who are not in Division R
- \(N_r\) - The number of employees in Division R
- \(N_{not-r}\) - The number of employees who are not in Division R

So, we don't know the number of employees who are not in Division R.

You can also use huge/tiny numbers to check your answer. If \(N_{not-r}=0\) or only 1 employee, S = 30K or will be very close to 30K. At the same time, if \(N_{not-r}>>1000\), S will be very close to 35K. So we need to know at least \(\frac{N_{not-r}}{N_r}\) ratio.
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Division R of Company Q has 1,000 employees. What is the average (arit 29 Mar 2026, 06:05
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