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Bunuel
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saswata4s
2x + y = –31, x = ?

(1) (y − 2)(y − 2) − 4 = 0
=> y^2 - 4 - 4 = 0
=>y^2 = 8
=> y = ±2√2
.

Although you get answer right, statement one has a problem. You deal with as difference of squares while it is not. You are right if it is (y − 2)(y + 2).
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If 2x + y = –31, what is the value of x?

(1) (y − 2)(y − 2) − 4 = 0

(y-2)^2 = 4

y-2 = +/- 2

y= 4 or y =0

Therefore, x has 2 answers

Insufficient

(2) y = 2

Apply in equation in prompt..........x has one answer

Sufficient

Answer: B
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