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tuanh135
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tuanh135
If x is a positive integer, what is the remainder when x is divided by 7?

(1) The remainder when x is divided by 4 is 3
(2) The remainder when x is divided by 5 is 1

We need to determine the remainder of x/7.

Statement One Alone:

The remainder when x is divided by 4 is 3.

We see that x can be values such as 3, 7, 11, 15, 19, 23, 27, 31, etc.

However, using those values, we get various remainders when dividing by 7. For example, when 3 is divided by 7, the remainder is 3, but when 7 is divided by 7, the remainder is 0. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

The remainder when x is divided by 5 is 1.

We see that x can be values such as 1, 6, 11, 16, 21, 26, 31, etc.

However, using those values, we get various remainders when dividing by 7. For example, when 1 is divided by 7, the remainder is 1, but when 6 is divided by 7, the remainder is 6. Statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using the two statements together, we see that x could be 11 or 31. When x = 11, the remainder is 4 when 11 is divided by 7. However, when x = 31, the remainder is 3 when 31 is divided by 7.

Answer: E
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niks18 gmatbusters Bunuel chetan2u VeritasPrepKarishma amanvermagmat

Is there any other approach than plugging numbers to solve this Q?
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Hi
The approach taken by GMATprepnow is a nice one.
Try to practice and be used to this approach, this will help in similar questions.

adkikani


Is there any other approach than plugging numbers to solve this Q?
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gmatbusters

I could not understand approach by GMATPrepNow , esp this quote:

Quote:
If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.

I understood niks18 approached this by using:

Dividend = (Integer Quotient) * Divisor + Remainder

Let me know if my understanding is correct or flawed.
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Hi
Both are same approach, it is the matter of presentation that differs.
"If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc. "
Example to explain this: Here D is Divisor, R is Remainder
let N when divided by 2 gives remainder as 1.
then N can be 1, 2+1, 2*2+1, 3*2+1...
N can be 1, 3, 5, 7... so on...

Grasp the concept, terminology doesn't matter much.


adkikani
gmatbusters

I could not understand approach by GMATPrepNow , esp this quote:

Quote:
If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.

I understood niks18 approached this by using:

Dividend = (Integer Quotient) * Divisor + Remainder

Let me know if my understanding is correct or flawed.
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adkikani
gmatbusters

I could not understand approach by GMATPrepNow , esp this quote:

Quote:
If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.

I understood niks18 approached this by using:

Dividend = (Integer Quotient) * Divisor + Remainder

Let me know if my understanding is correct or flawed.

Here are three important things you need to know about remainders:

If N divided by D equals Q with remainder R, then N = DQ + R
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3

If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.
For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.

When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D
For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0

RELATED VIDEO

Cheers,
Brent
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tuanh135
If x is a positive integer, what is the remainder when x is divided by 7?

(1) The remainder when x is divided by 4 is 3
(2) The remainder when x is divided by 5 is 1



Here,
Stmnt 1: x = 4a + 3
So x = 3, 7, 11, 15...
Stmnt 2: x = 5b + 1
So x = 1, 6, 11, 16 ...

First number of both types is 11. Next such number will be 11 + 4*5 = 31.
11 divided by 7 will give remainder 4.
31 divided by 7 will give remainder 3 and so on...

So answer is (E)
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Hey JeffTargetTestPrep, BrentGMATPrepNow

Is there a better approach than listing numbers all the way to 31? I feel like there must be a better approach than this. On the actual exam, under time pressure, one might not unroll values all the way to 31.
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