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05 Nov 2017, 02:12
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
57% (01:05) correct
43%
(00:45)
wrong
based on 106
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Is 1/x greater than 1/y?
(1) x is greater than 1.
(2) x is less than y.
(1) x is greater than 1.
(2) x is less than y.
05 Nov 2017, 06:13
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Bunuel
The answer should be C as follows.
(1) x is greater than 1.
Since only value of x is give, y can be anything
INSUFFICIENT
(2) x is less than y
Here, there will be 3 cases
Case 1: When both x and y are positive
E.G. let x=2 and y=3
\(\frac{1}{x}=\frac{1}{2}=0.5\)
\(\frac{1}{y}=\frac{1}{3}=0.333\)
in this case \(\frac{1}{x}>\frac{1}{y}\)
Case 2: When x is negative and y is positive
E.G. x = -2 and y=3
\(\frac{1}{x}=\frac{1}{(-2)}= -0.5\)
\(\frac{1}{y}=\frac{1}{3}=0.333\)
in this case \(\frac{1}{x}<\frac{1}{y}\)
Case 2: When both x and y are negative
E.G. x = -2 and y=-1 (Since x<y)
\(\frac{1}{x}=\frac{1}{(-2)}= -0.5\)
\(\frac{1}{y}=\frac{1}{(-1)}= -1\)
in this case \(\frac{1}{x}<\frac{1}{y}\)
ICUFFICIENT
Note: Case 3 was really not required to be considered as case 1 and case 2 themselves produced the conflicting results.
Combining both, the condition will become, x<y and x is greater than 1. This will be an spacial scenario of case 1 of statement 2 in the question.
Since x>1, both x and y will be positive
E.G. x=2 and y=3
\(\frac{1}{x}=\frac{1}{2}=0.5\)
\(\frac{1}{y}=\frac{1}{3}=0.333\)
in this case \(\frac{1}{x}>\frac{1}{y}\)
SUFFICIENTS
Hence, answer is C
05 Nov 2017, 07:20
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Please correct me if I am wrong.
What the question is asking is 1/x > 1/y
So can we not say -x>-y
and hence x<y I think this is what they are asking.
So only B statement proves it.
Please advise. Thanks
What the question is asking is 1/x > 1/y
So can we not say -x>-y
and hence x<y I think this is what they are asking.
So only B statement proves it.
Please advise. Thanks
