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Bunuel
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Bunuel

If triangles ABC and CDE are each equilateral, what is the sum of the perimeters of the two triangles?

(1) Line segment AE measures 25 meters.

(2) Side BC is 2/3 as long as side DE.

Attachment:
Triangle_Problem.png
I will also go with statement A as we assume ac as X and CE as y then perimeter= 3x+3y= 3(x+y)=3 (25)
and b is insufficient as we don't have any value of any side.
IMO A
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St 1: AE = 25

Total perimeter = 3*AC + 3*CE = 3(AC+CE) = 3(AE) = 3*25
Sufficient

St 2: \(BC = \frac{2}{3} DE\)

Total perimeter = 3*BC + 3*DE = 3* [(\(\frac{2}{3}\))*DE] + 3*DE
= 2DE + 3DE = 5*DE

Not unique value, so insufficient.

So, answer is A.
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C-trap problem.

If triangles ABC and CDE are each equilateral, what is the sum of the perimeters of the two triangles?

(1) Line segment AE measures 25 meters.
At first glance, this might seem insufficient b/c we dont' actually know the lengths of AC or CE, but that's actually irrelevant because no matter how we slice it, the sum of the perimeters of both triangles will be the same

AC = 10, CE = 15 ---> Ptotal = 75
AC = 5, CE = 20 ---> Ptotal = 75
AC = 12.5, CE = 12.5 ---> Ptotal = 75

Sufficient.

(2) Side BC is 2/3 as long as side DE.
BC = 2/3DE
Clearly insufficient.

A is the answer.
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