Last visit was: 30 Apr 2026, 13:54 It is currently 30 Apr 2026, 13:54
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
20,910
 [15]
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,910
 [15]
Kudos
Add Kudos
15
Bookmarks
Bookmark this Post
User avatar
niks18
User avatar
Retired Moderator
Joined: 25 Feb 2013
Last visit: 30 Jun 2021
Posts: 862
Own Kudos:
1,807
 [1]
Given Kudos: 54
Location: India
GPA: 3.82
Products:
Posts: 862
Kudos: 1,807
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
20,910
 [1]
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,910
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
avatar
MarcoAD
Joined: 09 Jun 2018
Last visit: 24 Feb 2019
Posts: 5
Own Kudos:
Posts: 5
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
EgmatQuantExpert

Solution:



The units digit of the expression \(7^X + 9^{X+3}\) will end with a zero, only when \(X\) is of the form \(4k\), i.e., a multiple of \(4\).
Step 1: Analyse Statement 1:
\(2^X\) is odd.
    • As per our conceptual knowledge, any even number when raised to a power will result in an even number only.
    • However, this is not always true.
      o Consider the example when an even number is raised to the power 0.
      o It has been taught in our concept file that any number (except 0) when raised to the power 0, will yield 1 as the answer.
         So, for 2X to be odd, X should be equal to 0.
Since 0 can be written in the form of 4k, where k =0,
Statement 1 alone is sufficient to answer the question.
Step 2: Analyse Statement 2:
\((2X+2)\) is Even.
    • \(2X\) is always even irrespective of the even-odd nature of \(X\).
      o This is because \(X\) is multiplied by an even number (2), and from our conceptual knowledge we know that,
      o Even * Even = Even
      o Even * Odd = Even
    • \(2\) is an even number
    • Therefore, from this statement, the even-odd nature of X cannot be determined.

Since we do not know the exact even-odd nature of X,
Statement 2 alone is NOT sufficient to answer the question.
Hence, we can eliminate answer choice B.
Step 3: Combine both Statements:
This step is not required since we already got a unique answer in step 3.
Correct Answer: Option C

Dear Payal,

perfect explanation, thanks. Just a typo in your write-up, correct answer is A, not C
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,910
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MarcoAD

Dear Payal,

perfect explanation, thanks. Just a typo in your write-up, correct answer is A, not C

Hey MarcoAD,
Thanks for pointing out the typo. We have rectified it. :)
avatar
xiaoxueren
Joined: 05 Aug 2018
Last visit: 01 Jan 2019
Posts: 5
Own Kudos:
Given Kudos: 157
Posts: 5
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
EgmatQuantExpert

Solution:



The units digit of the expression \(7^X + 9^{X+3}\) will end with a zero, only when \(X\) is of the form \(4k\), i.e., a multiple of \(4\).
Step 1: Analyse Statement 1:
\(2^X\) is odd.
    • As per our conceptual knowledge, any even number when raised to a power will result in an even number only.
    • However, this is not always true.
      o Consider the example when an even number is raised to the power 0.
      o It has been taught in our concept file that any number (except 0) when raised to the power 0, will yield 1 as the answer.
         So, for 2X to be odd, X should be equal to 0.
Since 0 can be written in the form of 4k, where k =0,
Statement 1 alone is sufficient to answer the question.
Step 2: Analyse Statement 2:
\((2X+2)\) is Even.
    • \(2X\) is always even irrespective of the even-odd nature of \(X\).
      o This is because \(X\) is multiplied by an even number (2), and from our conceptual knowledge we know that,
      o Even * Even = Even
      o Even * Odd = Even
    • \(2\) is an even number
    • Therefore, from this statement, the even-odd nature of X cannot be determined.

Since we do not know the exact even-odd nature of X,
Statement 2 alone is NOT sufficient to answer the question.
Hence, we can eliminate answer choice B.
Step 3: Combine both Statements:
This step is not required since we already got a unique answer in step 3.
Correct Answer: Option A

Dear Payal ,
thanks for your answer
but i do not know why
the units digit of the expression 7X+9X+3
7
X
+
9
X
+
3
will end with a zero, only when X
X
is of the form 4k
4
k
, i.e., a multiple of 4
4

.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 39,011
Own Kudos:
Posts: 39,011
Kudos: 1,122
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
110017 posts
498 posts
212 posts