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18 May 2018, 05:13
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
74% (00:33) correct
26%
(00:35)
wrong
based on 413
sessions
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How many sides does polygon P have?
(1) All sides of P have equal lengths.
(2) The sum of the measures of the interior angles of P is \(1,440^{\circ}\)
(1) All sides of P have equal lengths.
(2) The sum of the measures of the interior angles of P is \(1,440^{\circ}\)
07 Jul 2018, 11:37
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For those wondering whether it matters if the polygon is regular or irregular, in this question it does not:
The sum of the interior angles of an n-sided polygon is always = (n-2) * 180
The sum of each of the angles is [(n-2) * 180]/n, if the polygon is regular.
Here they are just asking for the number of sides ('n'), not each of the interior angles of polygon.
The sum of the interior angles of an n-sided polygon is always = (n-2) * 180
The sum of each of the angles is [(n-2) * 180]/n, if the polygon is regular.
Here they are just asking for the number of sides ('n'), not each of the interior angles of polygon.
General Discussion
18 May 2018, 05:35
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alanforde800Maximus
(1) All sides of P have equal lengths. - Clearly Not Sufficient.
(2) The sum of the measures of the interior angles of P is \(1,440^{\circ}\) - Sufficient.
Sum of Interior angles of a polygon = \((n-2)\) * \(180^{\circ}\)=\(1440^{\circ}\) \(-> n=10.\)
As its a DS question so, if we know the formula, we know that B will be sufficient. We don't have to do the entire calculation.
Answer: (B).
