If x is an integer, is x odd? (1) x + (x + 1) + (x + 2) is odd (2) x^2

Question

If x is an integer, is x odd?

(1) x + (x + 1) + (x + 2) is odd

(2) x^2 is even

tejyr · Answer

It should be D.
1. only true when x=even
2+3+4=odd
for x odd given condition unsatisfied

2.x^2 is even only when x is even

sandman13 · Answer

Statement 1: 3x + 3 is odd. This implies x HAS to be even. Sufficient. 
Statement 2: x^2 is even. x is even. Sufficient.

Answer: D

baru · Answer

(1) x + (x + 1) + (x + 2) is odd

==> 3x+3 = odd 
 ==> E + O = O
  ==> 3*E = E ==> Sufficient

(2) x^2 is even
  ==> E*E = E-->Sufficient

Option D

nidhihiremath · Answer

Why havent we considered 0? In that case it wouldn't be applicable right

lavanyap531 · Answer

We can also consider x as -2, in that case;
-2 + -1 + 0 = -3 which is odd but x is even.

Which makes statement one not sufficient. So the answer should be E

Can someone please help!

Bunuel · Answer

(1) gives a NO answer to the question whether x is odd:

x + (x + 1) + (x + 2) = odd
3x + 3 = odd
3x = odd - 3 
3x = even
x = even

So, (1) is sufficient to conclude that x is NOT odd (recall that a definite NO answer is also sufficient).

0 is an even integer. So, x = 0 also gives a NO answer for each statement.

Prep Toolkit