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\(c=mt+b\). If the time is increased by \(10\), by how many dollars is the cost increased?

\(c(1)=mt+b\)
\(c(2)=m(t+10)+b\)

\(c(2)-c(1)=m(t+10)+b-(mt+b)=10m\) - increase will depend on value of m only

\(1) m=20\) - Suff
\(2) b=30\) - Not Suff

Answer (A)
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Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.

The increase in the cost when the time is increased by \(10\) is given by
\(m(t + 10) + b – (mt + b) = 10m\). As this depends on the variable m only,
condition 1) is sufficient.

Therefore, the answer is A.

Answer: A
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The simplest way here seems for me is to think about what slope of a line represents.

Here, delta(cost)/delta(time) = m <- the slope
we are given delta(time) = 10
We need slope for delta(cost)

Statement 1 is sufficient.

Statement 2 does not tell us what the slope is. Not sufficient.

Answer: A
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