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IMO B

Using Determinants is the fastest way to solve this question.

|3 0 1|
|6 0 1| = 3 (0-b) - 0(6-a)+1(6b-0), which essentially becomes -3b+6b . So if we get the value of b it is sufficient.
|a b 1|

So St2 gives us the value of b in a platter. Hence it is sufficient.

Took 38 secs
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