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Bunuel
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Solution


Given:
    • An expression, \(36x^2 – 108xy + 81y^2\)

To find:
    • The value of the given expression, \(36x^2 – 108xy + 81y^2\)

Analysing Statement 1
“3y – 2x = -4”
    • Squaring on both sides, we get,
      o \(4x^2 – 12xy + 9y^2 = 16\)
    • Multiplying this equation by 9, we get
      o \(36x^2 – 108xy + 81y^2 = 144\)

Therefore, Statement (1) ALONE is sufficient to answer this question

Analysing Statement 2
“x = 5/y”
    • Substituting this in the required expression, we get,
      o \(180/y^2 – 540 + 81y^2\)
      o We cannot find the value of this expression as we do not have any further information about y.

Therefore, Statement (2) ALONE is not sufficient to answer this question

Hence, the correct answer is option A.

Answer: A

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Bunuel
What is the value of \(36x^2 - 108xy + 81y^2\)?


(1) \(3y−2x=−4\)

(2) \(x=\frac{5}{y}\)

\(36x^2 - 108xy + 81y^2\)=\(9(4x^2 - 12xy + 9y^2)\)=\(9(3y-2x)^2\)

Re-phrased question stem:- \(9(3y-2x)^2\)=?

St1:- \(3y−2x=−4\)
Sufficient.(substitute the value of 3y-2x in rephrased question stem)

St2:- \(x=\frac{5}{y}\)
Insufficient. (Either value x or y is required)

Ans. (A)

Hello, would you kindly demonstrate the process of factoring the equation from
This
\(9(4x^2 - 12xy + 9y^2)\)

To this?
[m]9(3y-2x)^2[/m

Thank you!
Chris
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Same. If i knew i could factor ir like that tis would be a much easier question.
Clycos
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Bunuel
What is the value of \(36x^2 - 108xy + 81y^2\)?


(1) \(3y−2x=−4\)

(2) \(x=\frac{5}{y}\)

\(36x^2 - 108xy + 81y^2\)=\(9(4x^2 - 12xy + 9y^2)\)=\(9(3y-2x)^2\)

Re-phrased question stem:- \(9(3y-2x)^2\)=?

St1:- \(3y−2x=−4\)
Sufficient.(substitute the value of 3y-2x in rephrased question stem)

St2:- \(x=\frac{5}{y}\)
Insufficient. (Either value x or y is required)

Ans. (A)

Hello, would you kindly demonstrate the process of factoring the equation from
This
\(9(4x^2 - 12xy + 9y^2)\)

To this?
[m]9(3y-2x)^2[/m

Thank you!
Chris
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Bunuel
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spuntamb
Same. If i knew i could factor ir like that tis would be a much easier question.
Clycos
PKN
What is the value of \(36x^2 - 108xy + 81y^2\)?


(1) \(3y−2x=−4\)

(2) \(x=\frac{5}{y}\)


\(36x^2 - 108xy + 81y^2\)=\(9(4x^2 - 12xy + 9y^2)\)=\(9(3y-2x)^2\)

Re-phrased question stem:- \(9(3y-2x)^2\)=?

St1:- \(3y−2x=−4\)
Sufficient.(substitute the value of 3y-2x in rephrased question stem)

St2:- \(x=\frac{5}{y}\)
Insufficient. (Either value x or y is required)

Ans. (A)

Hello, would you kindly demonstrate the process of factoring the equation from
This
\(9(4x^2 - 12xy + 9y^2)\)

To this?
[m]9(3y-2x)^2[/m

Thank you!
Chris

To factor 9(4x^2 - 12xy + 9y^2) into 9(3y - 2x)^2, follow these steps:

Recognize that 4x^2 - 12xy + 9y^2 is a perfect square in the form (a - b)^2 = a^2 - 2ab + b^2.

Identify the square terms:

  • 4x^2 is (2x)^2.
  • 9y^2 is (3y)^2.
  • -12xy is -2(2x)(3y), which matches the middle term in the perfect square formula.

This confirms that 4x^2 - 12xy + 9y^2 can be rewritten as (3y - 2x)^2.
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