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07 Dec 2018, 09:38
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Difficulty:
65%
(hard)
Question Stats:
42% (01:23) correct
58%
(01:23)
wrong
based on 147
sessions
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What is the value of k?
(1) \(k^2-5k-66=0\)
(2) \(\frac{2k}{k^2+5k}=\frac{1}{8}\)
(1) \(k^2-5k-66=0\)
(2) \(\frac{2k}{k^2+5k}=\frac{1}{8}\)
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07 Dec 2018, 11:41
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for statement 1:
k2−5k−66=0
(k-11)(k+6)=0
so k=11 or k=(-6)
so insufficient
for statement 2:
16k = k^2 + 5k
k^2 - 11k = 0
k(k-11) = 0
apparently, k = 11 or k = 0
however, k = 0 can't be substituted in the original equation since it will set 0 as a denominator which has no meaning.
this ends with the value of k = 11
so sufficient.
I hope I didn't miss any tricks.
k2−5k−66=0
(k-11)(k+6)=0
so k=11 or k=(-6)
so insufficient
for statement 2:
16k = k^2 + 5k
k^2 - 11k = 0
k(k-11) = 0
apparently, k = 11 or k = 0
however, k = 0 can't be substituted in the original equation since it will set 0 as a denominator which has no meaning.
this ends with the value of k = 11
so sufficient.
I hope I didn't miss any tricks.
08 Dec 2018, 09:29
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Hey Mahmoudfawzy83
i'm newbie in GMAT...
so, if the data gives me TWO VALUES about "k", can't I accept that the value of k is a SOLUTION SET?
I agree with you, but i have to assume that "value" means an unique number value (and assumption is for CR questions kkkk)
i'm newbie in GMAT...
so, if the data gives me TWO VALUES about "k", can't I accept that the value of k is a SOLUTION SET?
I agree with you, but i have to assume that "value" means an unique number value (and assumption is for CR questions kkkk)
