Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
50% (02:41) correct
50%
(02:30)
wrong
based on 180
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of #, if # represents the tens digit of an integer K and K = 69746#6
(1) K/3 is divisible by 8
(2) K is divisible by 12
(1) K/3 is divisible by 8
(2) K is divisible by 12
05 Jul 2019, 04:49
Kudos
Bookmarks
Sherel
Looking at Statement 2 alone first, if the number is divisible by 12, it is divisible by 4 and by 3. If it's divisible by 4, then its last two digits form a number divisible by 4, and so "#6" must be divisible by 4. Since 16, 36, 56, 76, and 96 are divisible by 4, that just tells us # is odd. But 69746#6 must also be divisible by 3, so its digits must sum to a multiple of 3. Plugging in odd values for #, we find # can be 1 or can be 7, and Statement 2 is not sufficient.
Statement 1 tells us k is divisible by 3 (though it really needs to say that k/3 is an integer) and by 8. Any number divisible by 3 and 8 is certainly divisible by 3 and 4, and we found above that # can only be 1 and 7 if we can divide by 3 and 4, so we only need to check whether # can be 1 and whether it can be 7. If a number is divisible by 8, its last three digits form a multiple of 8, and since 616 is divisible by 8, and 676 is not, the value of # must be 1, and Statement 1 is sufficient.
So the answer is A, not sure where the posted OA of "D" comes from but it's not correct.
05 Jul 2019, 04:59
Kudos
Bookmarks
This is a question which requires us to know the basic divisibility rules.
# is the tens digit of the number. Hence, it can take any value between 0 to 9. This is a crucial piece we cannot forget when we are trying to find the value of the digit of a number.
From statement I, because K/3 is divisible by 8, we can say,
\(\frac{K}{3}\) = 8* Integer which is to say that K is a multiple of 24.
This means that the sum of the digits of K should be a multiple of 3 and the last 3 digits should be a multiple of 8.
Sum of digits of K = 38 + #. For this to be a multiple of 3, # can be 1 or 4 or 7. Only when # = 1, 616 is a multiple of 8. In the other two cases, 646 and 676 are not multiples of 8 and hence K will not be a multiple of 3.
We can say uniquely that # = 1. Statement I alone is sufficient.
Answer options B, C and E can be eliminated. Possible answer options are A or D.
From statement II, because K is divisible by 12, K should be divisible by both 4 and 3. So, the sum of the digits should be a multiple of 3 and the last 2 digits should be divisible by 4.
From question data, sum of digits = 38 + #. As we saw with statement I, # can be 1 or 4 or 7. But, when #=1 or # = 7, the last two digits yield 16 or 76, which are multiples of 4.
Here, we cannot definitely say #=1 or # = 7. Statement II alone is insufficient.
Answer option D can be eliminated. The correct answer option is A.
Hope this helps!
# is the tens digit of the number. Hence, it can take any value between 0 to 9. This is a crucial piece we cannot forget when we are trying to find the value of the digit of a number.
From statement I, because K/3 is divisible by 8, we can say,
\(\frac{K}{3}\) = 8* Integer which is to say that K is a multiple of 24.
This means that the sum of the digits of K should be a multiple of 3 and the last 3 digits should be a multiple of 8.
Sum of digits of K = 38 + #. For this to be a multiple of 3, # can be 1 or 4 or 7. Only when # = 1, 616 is a multiple of 8. In the other two cases, 646 and 676 are not multiples of 8 and hence K will not be a multiple of 3.
We can say uniquely that # = 1. Statement I alone is sufficient.
Answer options B, C and E can be eliminated. Possible answer options are A or D.
From statement II, because K is divisible by 12, K should be divisible by both 4 and 3. So, the sum of the digits should be a multiple of 3 and the last 2 digits should be divisible by 4.
From question data, sum of digits = 38 + #. As we saw with statement I, # can be 1 or 4 or 7. But, when #=1 or # = 7, the last two digits yield 16 or 76, which are multiples of 4.
Here, we cannot definitely say #=1 or # = 7. Statement II alone is insufficient.
Answer option D can be eliminated. The correct answer option is A.
Hope this helps!
