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20 Aug 2019, 02:12
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
88% (01:03) correct
12%
(01:18)
wrong
based on 42
sessions
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The value of an investment increased according to a variable annual rate such that its value in 2006 was 1.43 times its value in 1998. What was the value of the investment in 1998?
(1) The value was $373.80 more in 2006 than in 1998.
(2) The value of the investment was $1243.11 in 2006.
(1) The value was $373.80 more in 2006 than in 1998.
(2) The value of the investment was $1243.11 in 2006.
Archit3110
Major Poster
20 Aug 2019, 04:07
Kudos
Bookmarks
Bunuel
given
1998 = x and 2006 ; 1.43x
#1
The value was $373.80 more in 2006 than in 1998.
1.43x=373.8+x
solve for x ; 869 sufficient
#2
The value of the investment was $1243.11 in 2006.[/quote]
1.43x=1243.11
x= 869
sufficient
IMO D
20 Aug 2019, 05:05
Kudos
Bookmarks
Bunuel
Given: The value of an investment increased according to a variable annual rate such that its value in 2006 was 1.43 times its value in 1998.
Asked: What was the value of the investment in 1998?
Let us assume that the value of the investment in 1998 be x.
(1) The value was $373.80 more in 2006 than in 1998.
1.43x - x = $373.8
x = 373.8/.43 = $869.3
SUFFICIENT
(2) The value of the investment was $1243.11 in 2006.
1.43x = $1243.11
x = 1243.11/1.43 = $869.3
SUFFICIENT
IMO D
