Last visit was: 28 Apr 2026, 11:29 It is currently 28 Apr 2026, 11:29
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
Events & Promotions
User avatar
freedom128
Joined: 30 Sep 2017
Last visit: 01 Oct 2020
Posts: 939
Own Kudos:
1,377
 [7]
Given Kudos: 402
GMAT 1: 720 Q49 V40
GPA: 3.8
Products:
GMAT 1: 720 Q49 V40
Posts: 939
Kudos: 1,377
 [7]
2
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
User avatar
freedom128
Joined: 30 Sep 2017
Last visit: 01 Oct 2020
Posts: 939
Own Kudos:
1,377
 [2]
Given Kudos: 402
GMAT 1: 720 Q49 V40
GPA: 3.8
Products:
GMAT 1: 720 Q49 V40
Posts: 939
Kudos: 1,377
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
TheNightKing
Joined: 18 Dec 2017
Last visit: 20 Mar 2024
Posts: 1,124
Own Kudos:
Given Kudos: 421
Location: United States (KS)
GMAT 1: 600 Q46 V27
GMAT 1: 600 Q46 V27
Posts: 1,124
Kudos: 1,381
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
freedom128
Joined: 30 Sep 2017
Last visit: 01 Oct 2020
Posts: 939
Own Kudos:
Given Kudos: 402
GMAT 1: 720 Q49 V40
GPA: 3.8
Products:
GMAT 1: 720 Q49 V40
Posts: 939
Kudos: 1,377
Kudos
Add Kudos
Bookmarks
Bookmark this Post
TheNightKing
chondro48
If \(n\) is a non-zero integer, is \(\frac{n^2+n+1}{n}\) an integer?
(1) 4 is divisible by \(n\)
(2) \(n\) is an even integer

+1 kudo is appreciated

Statement 2 says: n is an even integer. But If I use n=2 in the equation it does not result in an integer (4+2+1)/2=7/2=3.5.
So how is B sufficient ?

Yes, that really means that if n is an even integer, \(\frac{2n^2+n+1}{n}\) is certainly not an integer.

Remember that DS problem is all about whether we have sufficient information given by the statement, so as to be able to confidently answer Yes/No to the question. You may want to see my explanation post above
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 28 Apr 2026
Posts: 5,989
Own Kudos:
5,862
 [1]
Given Kudos: 163
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,989
Kudos: 5,862
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
chondro48
If \(n\) is a non-zero integer, is \(\frac{n^2+n+1}{n}\) an integer?
(1) 4 is divisible by \(n\)
(2) \(n\) is an even integer

+1 kudo is appreciated

Given: \(n\) is a non-zero integer,

Asked: is \(\frac{n^2+n+1}{n}\) an integer?

(1) 4 is divisible by \(n\)
n= 1, 2 or 4
For n=1; the expression = 3 integer
For n=2; the expression = 7/2=3.5 not integer
For n= 4; the expression = 21/4 not integer
NOT SUFFICIENT

(2) \(n\) is an even integer.
If n= even; numerator is odd and denominator is even ; not an integer
SUFFICIENT

IMO B

Posted from my mobile device
User avatar
unraveled
Joined: 07 Mar 2019
Last visit: 10 Apr 2025
Posts: 2,706
Own Kudos:
2,332
 [1]
Given Kudos: 763
Location: India
WE:Sales (Energy)
Posts: 2,706
Kudos: 2,332
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
chondro48
Prasannathawait, lnm87, try this question and +1 :thumbup: is humbly welcome :)

First, simplify \(\frac{n^2+n+1}{n} = n+1+\frac{1}{n}\). In order \((n+1+\frac{1}{n})\) to be an integer, \(\frac{1}{n}\) has to be integer. This can only be achieved if \(n\) is \(-1\) or \(1\) since \(n\) has to be a non-zero integer.

(1) 4 is divisible by \(n\)
This statement implies that \(n\) can be \(-4,-2,-1,1,2,4\). No additional information to ascertain whether \(n\) is either \(-1\) or \(1\).
NOT SUFFICIENT

(2) \(n\) is an even integer
This statement implies that \(n\) must not be either \(-1\) or \(1\).
SUFFICIENT

Answer is (B)

Marked D. A mistake on my part that i thought n is a multiple of 4. Don't know how i got that crappy thing in my head while solving. :x
User avatar
Prasannathawait
Joined: 10 Aug 2018
Last visit: 15 Jun 2020
Posts: 215
Own Kudos:
152
 [1]
Given Kudos: 179
Location: India
Concentration: Strategy, Operations
WE:Operations (Energy)
Products:
Posts: 215
Kudos: 152
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Finally got 1 correct.
It's B.
Because the 2nd statement will give NO as an answer every time.
Thanks. Kudos given.
User avatar
exc4libur
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,680
Own Kudos:
1,469
 [2]
Given Kudos: 607
Location: United States
Posts: 1,680
Kudos: 1,469
 [2]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
chondro48
If \(n\) is a non-zero integer, is \(\frac{2n^2+n+1}{n}\) an integer?

(1) 4 is divisible by \(n\)
(2) \(n\) is an even integer

RULES
even/even = anything
odd/odd = odd or fraction
even/odd = even or fraction
odd/even = not defined or fraction

\(n=odd:\frac{2n^2+n+1}{n}=\frac{even+odd+odd}{odd}=\frac{even}{odd}=(even,fraction)\)

\(n=even:\frac{2n^2+n+1}{n}=\frac{even+even+odd}{even}=\frac{odd}{even}=(n/d,fraction)\)

(1) insufic

n is a factor of 4, n={1,2,4}=even,odd

(2) sufic

n=even; thus, the fraction is not an integer

Ans (B)
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,986
Own Kudos:
Posts: 38,986
Kudos: 1,119
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109950 posts
498 posts
212 posts