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satya2029
shridhar786
pq < 70, where both P and Q are distinct odd primes. Determine PQ.

Statement (1): PQ is one greater than a power of two.

Statement (2): The sum of the digits of PQ is a prime number.
From 1
PQ=32+1=33=3*11
PQ=64+1=65=5*13
NOT SUFFICIENT
From 2
PQ=65
PQ=41
Not sufficient
FROM 1 AND 2
PQ=65=64+1=5*13 and 6+5=11 a prime
Sufficient
C

Posted from my mobile device

Hey,
The solution given by you is good. However, there's just one small mistake. In statement 2, PQ = 41 is not a valid case. \(P*Q = 41*1\) and we know that P and Q are prime numbers, so P or Q cannot be 1.
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shridhar786
pq < 70, where both P and Q are distinct odd primes. Determine PQ.

Statement (1): PQ is one greater than a power of two.

Statement (2): The sum of the digits of PQ is a prime number.

Odd primes : 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37.. we don't need further as PQ will exceed 70. In fact PQ can be highest (19*3)= 57.

1) PQ can assume values like 9, 17, 33, 65. Among them 33(3*11) and 65(5*13) both meets the criteria given. Not sufficient
2) PQ can be 21 or 65. Not sufficient.
Togrther, PQ is 65. Suff.
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