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Bunuel
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If a and b are positive integers and the ratio \(\frac{a}{b}\) is expressed as a decimal, is \(\frac{a}{b}\) a terminating decimal?

(Statement1): 50 < a < 60
Let's say that a = 51,
--> if b=102, then \(\frac{a}{b}=\frac{51}{102}= 0.5\)(terminating decimal -YES)
--> if b=153, then \(\frac{a}{b} =\frac{51}{153} =\frac{1}{3}=0.333\)... (not terminating decimal -NO)
Insufficient

(Statement2): b = 3
\(\frac{a}{b}\) -decimal --> a cannot be the multiple of 3
--> \(\frac{a}{b}\) is never be terminating decimal (Always NO)
Sufficient

The answer is B.
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If a and b are positive integers and the ratio a/b is expressed as a decimal, is a/b a terminating decimal?

(1) 50 < a < 60
(2) b = 3

Terminating decimal we get integer is divisible by 5 or 2.
#1 insufficient as b not know
#2 b=3 insufficient as a not know
From 1&2
Sufficient as decimal will be terminating and non terminating
a=52,53,54...

IMO E

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(1) 50 < a < 60
(2) b = 3

clearly they are insufficient individually....
combining both we get a=51-59,b=3 then except for 51,54,57(a/b is an int) ....others whose result is a decimal is non-terminating....

OA:C
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Quote:
If a and b are positive integers and the ratio a/b is expressed as a decimal, is a/b a terminating decimal?

(1) 50 < a < 60
(2) b = 3

(1) Not sufficiency
(2) Not sufficiency
Combine (1) and (2)
if a = 51; b = 3 => 51/3 = 17
if a = 52; b=3 => 52/3 = 17.33333
=> Not sufficiency
=> Choice E
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exc4libur
Hey, is an integer a terminating decimal?

Yes, an integer can be considered as terminating decimal.
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