Last visit was: 27 Apr 2026, 07:28 It is currently 27 Apr 2026, 07:28
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 27 Apr 2026
Posts: 109,928
Own Kudos:
811,555
 [2]
Given Kudos: 105,914
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,928
Kudos: 811,555
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
lacktutor
Joined: 25 Jul 2018
Last visit: 23 Oct 2023
Posts: 658
Own Kudos:
Given Kudos: 69
Posts: 658
Kudos: 1,447
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
GMATBusters
User avatar
GMAT Tutor
Joined: 27 Oct 2017
Last visit: 23 Apr 2026
Posts: 1,922
Own Kudos:
Given Kudos: 241
WE:General Management (Education)
Expert
Expert reply
Posts: 1,922
Kudos: 6,862
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Uditakaushal1992
Joined: 12 Apr 2023
Last visit: 04 Apr 2024
Posts: 29
Own Kudos:
Given Kudos: 6
Posts: 29
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATBusters
Question Stem information: AC = 15, BC = 15*4/5 = 12

1) AB = 9
All three sides are known, hence, a unique triangle can be drawn, the area can be found out.
SUFFICIENT
2) Since AC is diametre and B lies on the circumference of the circle, hence the triangle ABC is a right-angled triangle with right angle at B. hence, a unique triangle can be drawn, the area can be found out.
SUFFICIENT

Answer = D

Bunuel
What is the area of triangle ABC with sides AC = 15 and Side BC=4/5*AC.

(1) Side AB = 9

(2) If a circle is drawn with segment AC as a diameter, then point B of triangle ABC lies on the circumference of such a circle.

Hi how can we confirm in statement 2 that the triangle is Right Angled Triangle?
User avatar
GMATBusters
User avatar
GMAT Tutor
Joined: 27 Oct 2017
Last visit: 23 Apr 2026
Posts: 1,922
Own Kudos:
Given Kudos: 241
WE:General Management (Education)
Expert
Expert reply
Posts: 1,922
Kudos: 6,862
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Angle in a semicircle is a right angle.

Whenever a triangle is inscribed in a circle with a side as a diameter, then the angle of the triangle opposite to diameter as a side will be a right angle. Hence, the triangle will be a right angled triangle.

Uditakaushal1992
GMATBusters
Question Stem information: AC = 15, BC = 15*4/5 = 12

1) AB = 9
All three sides are known, hence, a unique triangle can be drawn, the area can be found out.
SUFFICIENT
2) Since AC is diametre and B lies on the circumference of the circle, hence the triangle ABC is a right-angled triangle with right angle at B. hence, a unique triangle can be drawn, the area can be found out.
SUFFICIENT

Answer = D

Bunuel
What is the area of triangle ABC with sides AC = 15 and Side BC=4/5*AC.

(1) Side AB = 9

(2) If a circle is drawn with segment AC as a diameter, then point B of triangle ABC lies on the circumference of such a circle.

Hi how can we confirm in statement 2 that the triangle is Right Angled Triangle?

Posted from my mobile device
Moderators:
Math Expert
109928 posts
498 posts
212 posts