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23 Mar 2020, 06:40
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (01:42) correct
30%
(02:05)
wrong
based on 206
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In the list of numbers {a, b, c}, a is the average (arithmetic mean) of the list and b + c = 0. What is the standard deviation of a, b, and c?
(1) b − a = 2
(2) a − c = 2
(1) b − a = 2
(2) a − c = 2
26 Mar 2020, 03:54
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Bunuel
a is the average (arithmetic mean) of the list
--> a = (a + b + c)/3
--> a = a/3 [Since b + c = 0]
--> 3a - a = 0
--> 2a = 0 or a = 0
(1) b − a = 2
--> b - 0 = 2 --> b = 2
Given, b + c = 0 --> c = -b = -2
--> {a, b, c} = {0, 2, -2} --> Standard Deviation can be calculated --> Sufficient
(2) c − a = 2
--> c - 0 = 2 --> c = 2
Given, b + c = 0 --> b = -c = -2
--> {a, b, c} = {0, -2, 2} --> Standard Deviation can be calculated --> Sufficient
Option D
16 Nov 2020, 14:56
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I don't get it though. The two statements contradict each other. Either b=2 or b=-2.
Aren't the two statements supposed to always be in accordance with each other?
Aren't the two statements supposed to always be in accordance with each other?
