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abcdddddd
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Thus, \(2.86 < T ≤ 8.6 ⟹ 2.86 < 2.z < 2.95\)
 If we round off the numbers from 2.86 to 2.95, excluding both, to their nearest tenth digit, the result will always be 2.9.

Hi GMATWhizTeam,

How did 8.6 become 2.95? while the LHS (2.86) remained the same? Can you please explain that part!

Thank you

Hi,

We already know T=2.z hours. This means T will always be less than 3. So the range becomes 2.86 to 2.99.
We have obtained the range in the form of 2.zx, but we need it to be in the form of 2.z. For this, we need to round it to 1 decimal point while maintaining the units place as 2.
Therefore, the range becomes \(2.86 < T ≤ 8.6 ⟹ 2.86 < 2.z < 2.95\)
Any value > 2.95 will round it up to 3.

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abcdddddd
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Thus, \(2.86 < T ≤ 8.6 ⟹ 2.86 < 2.z < 2.95\)
 If we round off the numbers from 2.86 to 2.95, excluding both, to their nearest tenth digit, the result will always be 2.9.

Hi GMATWhizTeam,

How did 8.6 become 2.95? while the LHS (2.86) remained the same? Can you please explain that part!

Thank you

Heyabcdddddd

We only need to focus on the time which when rounded off to its tenth digit will be in the form of 2.z. So, according to the statement 1 even though we are getting time's range as \(2.86 < T ≤ 8.6 \), we are decreasing its upper limit to 2.95 i.e.\(2.86 < T < 2.95 \).
Now the question comes why are we decreasing it to less than 2.95 only? This is because if \(2.95 ≤ T ≤ 8.6\) and it is rounded off to it's tenth digit, the time won't be in the form of 2.z or the unit's digit of T won't be 2.
For example, if T = 2.95 then it's hundredth's digit is ≥ 5. So when it is rounded up to its tenth's digit the result will be 3.0

Hope that helps! :)

Regards,
GMATwhiz Team
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