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siddharthkapoor
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A total of $100,000 was invested in one year. A part of this amount ea 15 Jul 2020, 09:12
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65% (hard)

Question Stats:

61% (02:26) correct 39% (02:22) wrong based on 237 sessions

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A total of $100,000 was invested in one year. A part of this amount earned a simple annual interest at the rate of x percent, and the rest earned a simple annual interest at the rate of y percent. If the total interest earned by the $100,000 in one year was $2,600, what is the value of the amount that is invested at x percent?

(1)3x = 2y
(2) The interest that earned at the rate of y percent was 1,800
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C
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nick1816
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A total of $100,000 was invested in one year. A part of this amount ea 15 Jul 2020, 10:13
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\(\frac{P*x*}{100} + \frac{(100,000-P)*y}{100 }= 2600\)

We have 3 variables here and 1 equation.

We need 2 more equations to solve it.

Statement 1 and statement 2 combined will give you 2 distinct equations.

C

iamsiddharthkapoor
A total of $100,000 was invested in one year. A part of this amount earned a simple annual interest at the rate of x percent, and the rest earned a simple annual interest at the rate of y percent. If the total interest earned by the $100,000 in one year was $2,600, what is the value of the amount that is invested at x percent?

(1)3x = 2y
(2) The interest that earned at the rate of y percent was 1,800
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fmcgee1
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A total of $100,000 was invested in one year. A part of this amount ea 18 Jul 2020, 15:41
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nick1816
\(\frac{P*x*}{100} + \frac{(100,000-P)*y}{100 }= 2600\)

We have 3 variables here and 1 equation.

We need 2 more equations to solve it.

Statement 1 and statement 2 combined will give you 2 distinct equations.

C

iamsiddharthkapoor
A total of $100,000 was invested in one year. A part of this amount earned a simple annual interest at the rate of x percent, and the rest earned a simple annual interest at the rate of y percent. If the total interest earned by the $100,000 in one year was $2,600, what is the value of the amount that is invested at x percent?

(1)3x = 2y
(2) The interest that earned at the rate of y percent was 1,800
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I can't seem to get your equation to work with the equations in statement 1 and 2.
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A total of $100,000 was invested in one year. A part of this amount ea 19 Jul 2020, 00:41
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We want to know the value of the amount that is invested at x percent

From statement 2 -

\(\frac{(100,000-P)*y}{100 }= 1800\)........(1)

Hence, \(\frac{P*x}{100} = 2600-1800 = 800\)

or P*x = 80000.........(2)

Now put \(y = \frac{3x}{2}\) (from statement 1) in equation (1)

\(\frac{(100,000-P)*3x}{200 }= 1800\)

(100000-P)*x = 120000.......(3)

Divide equation (2) by (3)

\(\frac{P}{100000-P} = \frac{2}{3}\)

\(3P = 200000 - 2P\)

P = 40,000 and x = 2



fmcgee1
nick1816
\(\frac{P*x*}{100} + \frac{(100,000-P)*y}{100 }= 2600\)

We have 3 variables here and 1 equation.

We need 2 more equations to solve it.

Statement 1 and statement 2 combined will give you 2 distinct equations.

C

iamsiddharthkapoor
A total of $100,000 was invested in one year. A part of this amount earned a simple annual interest at the rate of x percent, and the rest earned a simple annual interest at the rate of y percent. If the total interest earned by the $100,000 in one year was $2,600, what is the value of the amount that is invested at x percent?

(1)3x = 2y
(2) The interest that earned at the rate of y percent was 1,800

I can't seem to get your equation to work with the equations in statement 1 and 2.
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