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For statement 1, it runs until infinity so isn't technically the largest possible number imaginable the 'upper limit'? Maybe I am overthinking this.
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How can It be that A is not sufficient?

X/Y will be max for X max and Y min

Thus if according to A y is greater or equal than 1 then Y MIN =1
Then we know that X max is -1 (range is between zero and minus 50 excluded).

Thus max value is 1/1=1

What's wrong with this reasoning? If y grows then the number will decrease
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Analyze the question: -50 < x < 0, x and y are integers

I. -49 <= x <= -1, y >= 1, x/y is negative. The maximum value will be close to zero. So use -1 for x, as any other value will give a smaller x/y. y can be infinitely large and no definite value can be singled out. Hence insufficient.
II. y = -x, x/y = -1. Maximum value = -1. Sufficient.

Answer: B
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Scuven
How can It be that A is not sufficient?

X/Y will be max for X max and Y min

Thus if according to A y is greater or equal than 1 then Y MIN =1
Then we know that X max is -1 (range is between zero and minus 50 excluded).

Thus max value is 1/1=1

What's wrong with this reasoning? If y grows then the number will decrease

Scuven
Firstly, the max value can never be 1, it will always be negative in both the statements. Y goes to infinity, so you don't know the max value.
Obviously X=-1 for max considering max values. So if y =1, x/y=-1 and if y=2, x/y= -1/2 = -0.5
-0.5>-1.

Essentially as you keep on increasing the denominator, the absolute value of the fraction would keep on falling but the actual value will increase as the fraction is negative!

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