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E
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Difficulty:
85%
(hard)
Question Stats:
34% (01:44) correct
66%
(01:13)
wrong
based on 135
sessions
History
Date
Time
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Not Attempted Yet
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 29 Mar 2026
Posts: 3,088
Given Kudos: 1,510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
23 Oct 2020, 08:39
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To find: is x|y| > y^2 ?
(1) x>0
Case 1: X and y = 1
1*1 = 1*1 (x|y| is not greater than y^2)
Case 2: X = 1 and y = -2
1*|-2| = (-2)^2
2 < 4 (x|y| is less than y^2)
Case 3: X = 1 and y = 1/2
1/2 > 1/4 (x|y| is greater than y^2)
(Insufficient)
(2) x>y
Case 1: X = -1 and Y = -2
-2 < 4 (x|y| is less than y^2)
Case 2: X = 1 and y = -2
1*|-2| = (-2)^2
2 < 4 (x|y| is less than y^2)
Case 3: X = 1 and y = 1/2
1/2 > 1/4 (x|y| is greater than y^2)
(Insufficient)
Combining both:
Case 1: X = 1 and y = -2
1*|-2| = (-2)^2
2 < 4 (x|y| is less than y^2)
Case 2: X = 1 and y = 1/2
1/2 > 1/4 (x|y| is greater than y^2)
(Insufficient)
Answer is E
Posted from my mobile device
(1) x>0
Case 1: X and y = 1
1*1 = 1*1 (x|y| is not greater than y^2)
Case 2: X = 1 and y = -2
1*|-2| = (-2)^2
2 < 4 (x|y| is less than y^2)
Case 3: X = 1 and y = 1/2
1/2 > 1/4 (x|y| is greater than y^2)
(Insufficient)
(2) x>y
Case 1: X = -1 and Y = -2
-2 < 4 (x|y| is less than y^2)
Case 2: X = 1 and y = -2
1*|-2| = (-2)^2
2 < 4 (x|y| is less than y^2)
Case 3: X = 1 and y = 1/2
1/2 > 1/4 (x|y| is greater than y^2)
(Insufficient)
Combining both:
Case 1: X = 1 and y = -2
1*|-2| = (-2)^2
2 < 4 (x|y| is less than y^2)
Case 2: X = 1 and y = 1/2
1/2 > 1/4 (x|y| is greater than y^2)
(Insufficient)
Answer is E
Posted from my mobile device
Archit3110
Major Poster
23 Oct 2020, 10:31
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sjuniv32
target is \(x |y| > y^2\)
#1
\(x > 0\)
in that case value of y is not know insufficient
#2
x>y
we can have x=-1 & y = -2
-2>4 no
x=4 and y = 0
0=0 no
x=4 & y =1
4>1 ; yes
insufficient
from 1 &2
x is +ve so y can be any value <x
clearly insufficient
as y can be 0 or y can be any +ve value from o to x
insufficient
option E
